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Viefleur [7K]
3 years ago
13

how many liters of carbon dioxide are produced at STP when 295g or propane gas (C3H8) is reacted with excess oxygen? the other p

roduct is water vapor. write out balanced equation and then all calculation for credit.
Chemistry
1 answer:
LiRa [457]3 years ago
7 0
<span>The balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O

</span>1) first step is to<span> determine the molar mass you have to consult the periodic table and see the atomic mass of each element. If the element is repeated, for example 3 times, you multiple the atomic mass per 3.
C3H8= 12 x 3 + 1*8
= 44 g/mol

2)convert grams to moles so that everything will be in same unit.</span>
<span>moles are calculated by dividing mass by molar mass.
moles of C3H8= 295g / 44 g/mol
= 6.705 mol

3)By looking at the balanced equation, you can see that 1 mol of C3H8 will produce 3 moles of CO2. So if you have 6,705 moles, you will  obtain x moles of CO2:
1 C3H8--------3 CO2
6,705----------x  of CO2
x= 20,115 mol of CO2
</span>
4) At STP(<span>Standard Temperature and Pressure)</span> 1 mole of gas is equivalent to 22.4 liters.
1 mol of CO2-----22,4
20,115 -------------x liters
x= 20,115 x 22,4 =
450,6 liters.

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