metal have free electrons in their outer shell which make them generally good conductors of electricity. Example is the copper which is used for electrical wiring since is a good conductor of electricity. copper with electronic configuration of (Ar)4s2 has two free electrons in their outer most shell which allow it to conduct electricity.
Answer:
Concentration: 0.185M HX
Ka = 9.836x10⁻⁶
pKa = 5.01
Explanation:
A weak acid, HX, reacts with NaOH as follows:
HX + NaOH → NaX + H2O
<em>Where 1 mole of HX reacts with 1 mole of NaOH</em>
To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).
18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX
In 20.0mL = 0.0200L =
0.00370 moles HX / 0.0200L = 0.185M HX
The equilibrium of HX is:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
And Ka is defined as:
Ka = [H⁺] [X⁻] / [HX]
<em>Where [H⁺] = [X⁻] because comes from the same equilibrium</em>
As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M
Replacing:
Ka = [H⁺] [H⁺] / [HX]
Ka = [1.349x10⁻³M]² / [0.185M]
Ka = 9.836x10⁻⁶
pKa = -log Ka
<h3>pKa = 5.01</h3>
We know the law of conservation of mass
- It states that mass is neither formed nor destroyed in any chemical reaction.
- Mass of reactants=Mass of products.
Here
- Mg and I_2 are reactants
- MgI_2 is product with some yield.
- Mass of reactants=10+60.0=70.0g
- Mass of MgI_2=53.88g
- Mass of yield=Product-MgI_2=70-53.88=16.12g
Lets find the percentage
<h2>
Answer:HCl</h2>
Explanation:
For 
For 
The reaction between 
and 
is
→
So,one mole of requires one mole of
moles of requires moles of
But there are only 
moles of available.
will be consumed first.
So, is the limiting reagent.
