Answer:
Final velocity of electron, 
Explanation:
It is given that,
Electric field, E = 1.55 N/C
Initial velocity at point A, 
We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :
........(1)
a is the acceleration, 
We know that electric force, F = qE
Use above equation in equation (1) as:
v = 647302.09 m/s
or
So, the final velocity of the electron when it reaches point B is 
. Hence, this is the required solution.
So in a fluorescent light bulb the mercury atoms release the UV light. This UV light is absorbed by the phosphorous powder coating inside and this releases the visible light.
So your answer is phosphorous powder.
The best predictor of the radioactive nature of an isotope is the neutron-to-proton ratio of the atom. Isotopes are atoms of elements having the same number of protons however they don't have the same number of neutrons. Each isotope of an element will have different values of mass number.
The answer is 8 meters per second 8m/s because 200 divided by 25 is 8
Answer:
88km E
Explanation:
25 km is added already
then if we take the formula of speed(V)
V=d/t
and rearrange it to subject d (distance)
d= V x t
we get
d= 42km/h x 1.5hrs
we get
63 km
now if we add the already travelled 25 km to this additional distance
63km + 25km = 88km
Thus the final distance traversed by the ship from its origin is
88km E
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