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Serggg [28]
4 years ago
10

Which practice will help prevent data loss in case of a computer malfunction?

Physics
2 answers:
Gnoma [55]4 years ago
8 0
You should back-up your computer every few weeks (or as often as needed).

As soon as you suspect that your computer (or any other backup-able device) is too slow or "glitch-y" you should back-up your device before you lose any important files or data.

PREVENTING MALFUNCTION:
→ Always set your computer on a hard & flat surface.
→ Avoid downloading programs from unknown or non-trusted sources.
→ Avoid using your computer in a hot area.
→ Consider installing a virus/malware protection software on your computer.

Vedmedyk [2.9K]4 years ago
3 0

Schedule and perform regular backups of your data. Installing antivirus software and updating it regularly is a good practice. You must also back up your data on a regular basis. This helps to prevent data losses due to unforeseen events. Such events may include a virus threat or computer malfunction.

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A 1100 kg car pushes a 1800 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the
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Answer:The answer is 3000 N.

Force (F) is the multiplication of mass (m) and acceleration (a).

F = m · a

It is given:

mc = 1000 kg

mt = 2000 kg

total force: F = 4500 N 

total mass: m = mc + mt

Let's calculate acceleration which is common:

a = F/m = F/(mc + mt) = 4500/(1000 + 2000) = 4500/3000 = 1.5 m/s²

Now, when we know acceleration, let's calculate force on the truck:

Ft = mt · a = 2000 · 1.5 = 3000 N

Explanation:

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3 years ago
Integrated Science- 8th grade science
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Answer:

A. a rigorously tested explanation

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The angle of incidence is the angle between the the normal of the surface. and A. point of incidence B. reflected ray C. inciden
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Answer:

The right answer is (A)

Explanation:

Trust me

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what occurs when a swimmer pushes through the water to swim answers are (A) the water exerts a reaction force on the swimmer (B)
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One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
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Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

c) 0 J/K

d)S= 61.53 J/K

Explanation:

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T₁ = 745 K

T₂ = 101 K

Q= 7190 J

a)

The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

b)

The entropy change of reservoir 101 K

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S_2=71.18\ J/K

c)

The entropy change of the rod will be zero.

d)

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

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