Answer:
Cathode rays are streams of electrons observed in discharge tubes. In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a previously unknown negatively charged particle, which was later named the electron. Cathode-ray tubes (CRTs) use a focused beam of electrons deflected by electric or magnetic fields to render an image on a screen.
Answer:
The answer to your question is ΔH = -964.2 kJ
Explanation:
Data
Reaction 1 X + 12O₂ ⇒ XO ΔH = -607.3 kJ
Reaction 2 XCO₃ ⇒ XO + CO₂ ΔH = 356.9 kJ
ΔH for Reaction 3 X + 12O₂ + CO₂ ⇒ XCO₃
Process
1.- Write the Reaction 1 the same
2.- Invert the order of reaction 2, and change the sign of the Enthalpy
Reaction 1 X + 12O₂ ⇒ XO ΔH = -607.3 kJ
Reaction 2 XO + CO₂ ⇒ XCO₃ ΔH = - 356.9 kJ
3.- Sum up the reactions
X + 12O₂ + XO + CO₂ ⇒ XO + XCO₃
4.- Simplify
X + 12O₂ + CO₂ ⇒ XCO₃ ΔH = -964.2 kJ
Answer:
The rate of disappearance of 
is 0.0766 M/s.
Explanation:
Rate of the reaction = R
![R=-\frac{1}{1}\frac{d[C_2H_4]}{dt}=-\frac{1}{3}\frac{d[O_2]}{dt}](https://tex.z-dn.net/?f=R%3D-%5Cfrac%7B1%7D%7B1%7D%5Cfrac%7Bd%5BC_2H_4%5D%7D%7Bdt%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BO_2%5D%7D%7Bdt%7D)
[te]R=\frac{1}{2}\frac{d[CO_2]}{dt}=\frac{1}{2}\frac{d[H_2O]}{dt}[/tex]
Rate of disappearance of 
=0.23 M/s
Rate of disappearance of 
R =0.07666 M/s
Rate of disappearance of 
![\frac{d[C_2H_4]}{dt}=1\times 0.23 m/s=0.0766 M/s](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BC_2H_4%5D%7D%7Bdt%7D%3D1%5Ctimes%200.23%20m%2Fs%3D0.0766%20M%2Fs)
The rate of disappearance of is 0.0766 M/s.
Why wouldn’t that make a difference, hola mi, polo el coron
