Answer:
B. The media released popular information.
Explanation:
We do not share the power in our media.
Answer:
The flux of the electric field is 677.6 Nm²/C
Explanation:
Given that,
Area = 18 cm²
Charge = 6.0 nC
We need to calculate the flux of the electric field
Using Gauss's law
Where, q = charge
=permittivity of free space
Put the value into the formula
Hence, The flux of the electric field is 677.6 Nm²/C.
Answer:
291.1 Nm
Explanation:
Torque is simply the force required to cause a rotation, it is also sometimes referred to twisting force. In simple terms Torque is the rotational equivalent to the linear moment.
Calculating torque is a very simple process and is done with the following formula
T = F x d x SinФ
where
T = Toque (Nm)
F = Applied Force (N)
d = Distance from the axis of rotation (m)
Ф = Angle between F and d (Degree)
hence the torque is
T = 41 x 7.1 x Sin90
T = 291.1 Nm
Complete question is;
The energy flow to the earth from sunlight is about 1.4kW/m²
(a) Find the maximum values of the electric and magnetic fields for a sinusoidal wave of this intensity.
(b) The distance from the earth to the sun is about 1.5 × 10^(11) m. Find the total power radiated by the sun.
Answer:
A) E_max ≈ 1026 V/m
B_max = 3.46 × 10^(-6) T
B) P = 3.95 × 10^(26) W
Explanation:
We are given;
Intensity; I = 1.4kW/m² = 1400 W/m²
Formula for maximum value of electric field in relation to intensity is given as;
E_max = √(2I/(ε_o•c))
Where;
ε_o is electric constant = 8.85 × 10^(-12) C²/N.m²
c is speed of light = 3 × 10^(8) m/s
Thus;
E_max = √(2 × 1400)/(8.85 × 10^(-12) × 3 × 10^(8)))
E_max ≈ 1026 V/m
Formula for maximum magnetic field is;
B_max = E_max/c
B_max = 1026/(3 × 10^(8))
B_max = 3.46 × 10^(-6) T
Formula for the total power is;
P = IA
Where;
A is area = 4πr²
We are given;
Radius; r = 1.5 × 10^(11) m
A = 4π × (1.5 × 10^(11))² = 2.82 × 10^(23) m²
P = 1400 × 2.82 × 10^(23)
P = 3.95 × 10^(26) W
