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VMariaS [17]
3 years ago
9

Two people are holding up the ends of a 4.25-kg wooden plank. A 6.00-kg box sits in the center of the plank. What forces do the

people exert on the plank? Hint: The forces of the people must equal the forces acting on the box and the plank.
Physics
1 answer:
ira [324]3 years ago
5 0

The forces the people exert on the plank is 100.45N

<u>Explanation:</u>

Force of man 1 on plank = F_1

Force of man 2 on plank = F_2

\bold{\text{ \bold{ Acceleration due to gravity}} = 9.8 m/s^2}

Gravitational force on plank = \bold{m\times a = 4.25\times 9.8 = 41.65N}

Gravitational force on box = \bold{m\times a= 6\times 9.8 = 58.8N}

Given hint is forces of people is equal to forces on plank and box

\bold{\Rightarrow F-1 + F_2 = 41.65 + 58.8 = 100.45N}

in the state of equilibrium normal force is equal and opposite to gravitational force.  

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A strip of copper 190 µm thick and 4.20 mm wide is placed in a uniform magnetic field of magnitude B = 0.78 T, that is perpendic
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Answer:

V = 9.682 × 10^(-6) V

Explanation:

Given data

thick = 190 µm

wide = 4.20 mm

magnitude B = 0.78 T

current  i = 32 A

to find out

Calculate V

solution

we know v formula that is

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here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³

so put all value we get

V = magnitude× current / (no of charge carriers ×thickness × e

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3 0
2 years ago
An object is placed in front of a convex mirror with a radius of curvature of magnitude 10 cm. The mirror produces an image that
jek_recluse [69]

Answer:

u = - 20 cm

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f = \frac{R}{2} = \frac{10}{2} = 5 cm

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\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

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\frac{1}{u} = \frac{1}{5} - \frac{1}{4}

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3 years ago
1. A race car accelerates at a rate of 15.6 m/s. If it starts from rest, how much time till it
musickatia [10]

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2 years ago
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