A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m, 
how much elastic potential energy is stored in the spring? 700 J 1050 J 1575 J 4375 J
       
      
                
     
    
    
    
    
    2 answers:
            
              
              
                
                
Answer:
1575 J
Explanation:
The elastic potential energy of a string is given by:

where
k is the spring constant
 is the stretching/compression of the string with respect to its natural length
 is the stretching/compression of the string with respect to its natural length
For the spring in the problem, we have:
- Spring constant: 
- Stretching: 
Therefore, the elastic potential energy stored in the spring is

 
                                
             
                    
              
              
                
                
The answer is C. 1575 J. I just took this review.
 
                                
             
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