Answer: a) 7,00 centimeters
(b) 259. 19 feet
(c) 3110.28 inches
(d) 0.049 miles
Explanation:
(a) We know that 1 meter = 100 centimeters
Therefore,
![79\ m= 7,900\text{ centimeters}](https://tex.z-dn.net/?f=79%5C%20m%3D%207%2C900%5Ctext%7B%20centimeters%7D)
(b)Since 1 meter = 3.28084 feet
Then, ![79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}](https://tex.z-dn.net/?f=79%5C%20m%3D%2079%5Ctimes3.28084%3D259.18636%5Capprox%20259.19%5Ctext%7B%20feet%7D)
(c) Since, 1 feet = 12 inches.
![79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}](https://tex.z-dn.net/?f=79%5C%20m%3D259.19%5Ctext%7B%20feet%7D%3D259.19%5Ctimes12%3D3110.28%5Ctext%7B%20inches%7D)
(d) ![\text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}](https://tex.z-dn.net/?f=%5Ctext%7BSince%201%20feet%3D%20%7D%5Cdfrac%7B1%7D%7B5280%7D%5Ctext%7B%20mile%7D)
![79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}](https://tex.z-dn.net/?f=79%5C%20m%3D259.19%5Ctext%7B%20feet%7D%3D%5Cdfrac%7B259.19%7D%7B5280%7D%3D%090.0490890151515%5Capprox0.049%5Ctext%7B%20miles%7D)
Answer:
In 5 years or so, the sun will be awash in sunspots and more prone to violent bursts of magnetic activity.
Explanation
once the magnetic field weakens the area and cold plasma enters the area of the sunspot
Radius of nuclei is given by formula
![R = R_oA^{1/3}](https://tex.z-dn.net/?f=R%20%3D%20R_oA%5E%7B1%2F3%7D)
now we can say volume of the nuclei is given as
![V = \frac{4}{3}\pi R_o^3* A](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20R_o%5E3%2A%20A)
now the density is given as
density = mass / volume
mass of nuclei = mass of neutron + mass of protons
![m = z*m_p + (A- z)*m_n](https://tex.z-dn.net/?f=m%20%3D%20z%2Am_p%20%2B%20%28A-%20z%29%2Am_n)
![m_p = m_n = 1.008u](https://tex.z-dn.net/?f=m_p%20%3D%20m_n%20%3D%201.008u)
![m = A*1.008u](https://tex.z-dn.net/?f=m%20%3D%20A%2A1.008u)
Now density is given as
![\rho = \frac{A*1.008u}{\frac{4}{3}\pi R_0^3* A}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7BA%2A1.008u%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%20R_0%5E3%2A%20A%7D)
here we know that
= 1.2 fm
![\rho = \frac{1.008u}{\frac{4}{3}\pi*(1.2*10^{-15})^3}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7B1.008u%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%2A%281.2%2A10%5E%7B-15%7D%29%5E3%7D)
![\rho = 2.31 * 10^{17} kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%202.31%20%2A%2010%5E%7B17%7D%20kg%2Fm%5E3)
So from above we can say that density of all nuclei is almost same.
Answer:
B
endothermic: heat taking in
exothermic: heat given out
Explanation:
Nuclear reactions are the reactions in which nucleus of an atom changes either by splitting or joining with the nucleus of another atom.
There are two types of nuclear reactions.
- Nuclear fission - In this process, large atomic nuclei splits into smaller nuclei.
- Nuclear fusion - In this process, two small nuclei combine together to form a large nuclei.
Both nuclear fission and fusion processes involve nuclei of atoms.
For example, ![^{0}n + ^{235}_{92}U \rightarrow ^{236}_{92}U \rightarrow ^{144}_{56}Ba + ^{89}_{36}Kr + 3n + 177 MeV](https://tex.z-dn.net/?f=%5E%7B0%7Dn%20%2B%20%5E%7B235%7D_%7B92%7DU%20%5Crightarrow%20%5E%7B236%7D_%7B92%7DU%20%5Crightarrow%20%5E%7B144%7D_%7B56%7DBa%20%2B%20%5E%7B89%7D_%7B36%7DKr%20%2B%203n%20%2B%20177%20MeV)
Thus, we can conclude that statements which are true are as follows.
- Nuclear reactions involve the nuclei of atoms.
- The products of nuclear reactions are lighter than the reactants.