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UNO [17]
3 years ago
11

The distance-time graph for a faster moving object has a smaller slope than the graph for a slower moving object. True or false

Physics
2 answers:
allsm [11]3 years ago
6 0
False because faster moving slope would be going up and slower would be going down because its decreasing 
Dafna1 [17]3 years ago
6 0
The answer is false just trying to help as much as I can
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While an emf source supplies energy to a circuit, that energy is dissipated when the current passes through resistance. In deali
fredd [130]

The question is incomplete, the options are;

RI^2

I^2/R

R/I^2

R/V^2

RV^2

V^2/R

VI

VIR

Select all that apply

Answer:

P=RI^2

P=V^2/R

P=VI

Explanation:

Power is the rate at which energy is changing in a circuit. It is shown by the formulas outlined above from the group of answer choices. Since the current (I), voltage (V), and resistance (R) were mentioned in the question, any of three three formulas could be used to obtain the power drawn by the conductor.

7 0
3 years ago
(1 point) A pilot flies in a straight path for 1 hour and 30 min. She then makes a course correction, heading 10 degrees to the
kati45 [8]

Answer:

The pilot is 2214.22 miles from her starting position

Explanation:

Since the pilot is traveling at a constant speed of 635 mph, the total distance traveled can be easily found as follows:

1stleg: d_{1} = 1.5*635 = 952.5 mi\\2ndleg: d_{2} = 2*635 = 1270 mi

There was a 10 degrees deviation, so the angle between the trajectory of both legs is 170 degrees.

The distance we need to find is that from the start of the first leg to the end of the second leg, those three distances form a triangle and since the side we're interested in is opposite to the 170 degrees angle, we can determine its length by the law of cosines:

d_{3}^{2} =d_{1}^{2} + d_{2}^{2} -2*d_{1}*d_{2}*cos(170)\\d_{3}^{2} =952.5^{2} + 1270^{2} -2*952.5*1270*cos(170)\\d_{3}=2214.22mi

The pilot is 2214.22 miles from her starting position

8 0
3 years ago
A particle was moving in a straight line at 172.8 km/hr. If it decelerated over 120 meters to come to rest, find the time taken
Bezzdna [24]

Answer:

v=s/t

s=vt

t=s/v

t=(120×10‐³)/172.8

(the distance meters has been changed to kilometres)

t=1/1440 hrs

Given ,

8 0
2 years ago
Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has
dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

c=velocity of light

\lambda=wavelength of wave

E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

E=2.53\times 10^{-28}\ J

Hence the energy of the wave with wavelength 784 m is 2.53\times 10^{-28}\ J

7 0
3 years ago
What is one reason supporting genetic modifications to food
gtnhenbr [62]
Health and safety are two reasons
4 0
3 years ago
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