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vlada-n [284]
2 years ago
8

When light bends as it passes from one transparent object to another, the light is

Chemistry
2 answers:
kirza4 [7]2 years ago
7 0
When light passes from one transparent object, this is called refraction


Ulleksa [173]2 years ago
4 0

Answer: refraction of light

Explanation:

Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another. This bending by refraction makes it possible for us to have lenses, magnifying glasses, prisms and rainbows

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How many particles of CuCr2O7 are present in a 64.5 gram sample?
kow [346]
<h3>Answer:</h3>

1.39 × 10²³ particles CuCr₂O₇

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 64.5 g CuCr₂O₇

[Solve] particles CuCr₂O₇

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cu - 63.55 g/mol

[PT] Molar Mass of Cr - 52.00 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CuCr₂O₇ - 63.55 + 2(52.00) + 7(16.00) = 279.55 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 64.5 \ g \ CuCr_2O_7(\frac{1 \ mol \ CuCr_2O_7}{279.55 \ g \ CuCr_2O_7})(\frac{6.022 \cdot 10^{23} \ particles \ CuCr_2O_7}{1 \ mol \ CuCr_2O_7})
  2. [DA] Divide/Multiply [Cancel out units]:                                                         \displaystyle 1.38944 \cdot 10^{23} \ particles \ CuCr_2O_7

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.38944 × 10²³ particles CuCr₂O₇ ≈ 1.39 × 10²³ particles CuCr₂O₇

8 0
3 years ago
Thermal decomposition of magnesium nitrate and magnesium hydroxide <br><br>​
iragen [17]

Explanation:

hope it will help you. Wishing a nice day. enjoy with your answer

8 0
2 years ago
Zinc metal can be obtained from Zinc Oxide by reaction at high temperature with CO. The CO is obtained from burning C in limited
bonufazy [111]

Answer:

(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)

2C(s) + O2(g) ---------> 2CO(g)

(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)

3 0
3 years ago
You could add aquous hydrochloric to the solution to precipitate out silver chloride. What volume of a 0.130 M aqueous hydrochlo
Mila [183]
1) Chemical reaction: AgNO₃ + HCl → AgCl + HNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(HCl) = 1 : 1.
0,00675 mol : n(HCl) = 1 : 1.
n(HCl) = 0,00675 mol.
V(HCl) = n(HCl) ÷ c(HCl).
V(HCl) = 0,00675 mol ÷ 0,130 mol/L.
V(HCl) = 0,0519 L = 51,92 ml.

2) 1) Chemical reaction: AgNO₃ + KCl → AgCl + KNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(KCl) = 1 : 1.
0,00675 mol : n(KCl) = 1 : 1.
n(KCl) = 0,00675 mol.
m(KCl) = n(KCl) · M(KCl).
m(KCl) = 0,00675 mol · 74,55 g/mol.
m(KCl) = 0,503 g.
n - amount of substance.
M - molar mass.
5 0
3 years ago
How many moles are in 3.01 x 10 atoms of magnesium
Fiesta28 [93]
There are 3.01 moles. round to 3 if it asks for a whole number 
7 0
2 years ago
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