Answer:
3.1 L
Explanation:
Step 1: Given data
- Mass of oxygen (m): 3.1 g
Step 2: Calculate the moles of oxygen
The molar mass of oxygen is 32.00 g/mol.
Step 3: Calculate the volume of the container
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.097 mol × (0.0821 atm.L/mol.K) × 390 K / 1.00 atm
V = 3.1 L
The correct answer is D.
I hope that helped! c:
Answer: The mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.
Explanation:
Given: Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 750 mm Hg (1 mm Hg = 0.00131579 atm) = 0.98 atm
Formula used to calculate moles is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Moles is the mass of a substance divided by its molar mass. So, mass of (molar mass = 37.99 g/mol) is calculated as follows.
Thus, we can conclude that the mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.