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4 years ago

How might an intense solar storm affect people on Earth?

Physics

1 answer:

kow [346]4 years ago

8 0

An intense solar storm COULD disrupt communications and damage the power grid. <em> (A)</em>

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What happens to the electric potential energy of a negatively charged ion as it moves through the water from the negative probe

Nataly [62]

Answer:

Decreases.

Explanation:

Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.

When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.

Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.

5 0

4 years ago

2 Which is true of a parallel circuit?

mars1129 [50]

Answer:

fxb

Explanation:bfffffffff

8 0

3 years ago

a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string. The string is hung over a pulley as shown in t

svet-max [94.6K]

The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately

<h3>What are we to consider in equilibrium ?</h3>

Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.

Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.

The acceleration at which they will both move will be;

a = ( $m_{1}$ - $m_{2}$ ) / ( $m_{1}$ + $m_{2}$ )

a = (5.75 - 3.53) / (5.75 + 3.53)

a = 2.22 / 9.28

a = 0.24 m/s²

Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m

We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.

v² = u² + 2as

since u =0

v² = 2 × 0.24 × 2.47

v² = 1.1856

v = √1.19

v = 1.0888 m/s

Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately

Learn more about Equilibrium here: brainly.com/question/517289

#SPJ1

5 0

2 years ago

3. The atmospheres of Mars and Venus are mostly carbon dioxide. Earth'satmosphere contains only a fraction of a percent of carbo

maria [59]

Answer:

Earth's atmosphere is a mixture of nitrogen (79%), oxygen (20%), and a small fraction of carbon dioxide, water vapours and other gases. However, the atmospheres on Venus and Mars mainly consist of carbon dioxide.

Explanation:

3 0

3 years ago

Consider a mass-spring system. The spring has a spring constant 2.17e 3 N/m. On the end is a mass of 4.71 kg. You start at equil

Novosadov [1.4K]

Answer:

7.4 cm

Explanation:

K = 2.17 x 10^3 N/m

m = 4.71 kg

v = 1.78 m/s (It is maximum velocity)

The angular velocity

$\omega =\sqrt{\frac{k}{m}}$

$\omega =\sqrt{\frac{2.71\times 10^{3}}{4.71}}$

ω = 24 rad/s

Maximum velocity, v = ω x A

Where, A be the maximum displacement

1.78 = 24 x A

A = 0.074 m = 7.4 cm

8 0

4 years ago