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Wewaii [24]
4 years ago
15

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Potassium metal is exposed to an atmo

sphere of chlorine gas. (b) Strontium oxide is added to water. (c) A fresh surface of lithium metal is exposed to oxygen gas. (d) Sodium metal reacts with molten sulfur.
Chemistry
1 answer:
Yanka [14]4 years ago
5 0

Answer: The equations of the above reactions are shown below

Explanation:

(a)

2K(s) + Cl2(g) ==> 2 KCl(s)

(b)

SrO(s) + H2O(aq) ==> Sr(OH)2(aq)

(c)

4Li(s) + O2(g) ==> 2Li2O(s)

(d)

2Na(s) + S (l) ===> Na2S

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3 years ago
At constant temperature, 534 mL of a gas at 894 torr is compressed to 167 mL What is the new pressure in atmospheres?
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Answer:

3.762 atm.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

<em>(P₁V₁) = (P₂V₂)</em>

<em></em>

  • Knowing that:

P₁ = 894.0 torr, V₁ = 534.0 mL,

P₂ = ??? torr, V₂ = 167.0 mL.

  • Applying in the above equation

(P₁V₁) = (P₂V₂)

<em>∴ P₂ = (P₁V₁)/V₂</em> = (894.0 torr)(534.0 mL)/(167.0 mL) = <em>2859 torr.</em>

  • To convert from torr to atm:

1.0 atm = 760.0 torr.

<em>∴ P₂ </em>= (2859 torr)(1.0 atm/760 torr) = <em>3.762 atm.</em>

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