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PtichkaEL [24]
3 years ago
5

A. How long (in ns) does it take light to travel 1.0 m in a vacuum?

Physics
1 answer:
suter [353]3 years ago
4 0

Answer:

a) 3.33 ns

b) Water distance = 0.75 m

Glass distance = 0.66 m

Diamond distance = 0.41 m

Explanation:

We take the speed of light, c = m/s.

Speed = distance/time

Time = distance/speed

a)

t=\dfrac{1}{3.0\times10^{8}}=3.33\times10^{-9}

t = 3.33 ns

b)

Refractive index, n = speed of light in vacuum / speed of light in medium

n=\dfrac{c}{s}

s=\dfrac{c}{n}

d=s\times t

d=\dfrac{c}{n}\times \dfrac{1}{c}

d=\dfrac{1}{n}

Thus, the distance traveled in the same time is numerically equal to the reciprocal of the refractive index.

For water n = 1.333

d = 1/1.333 = 0.75 m

For glass n = 1.517

d = 0.66 m

For diamond n = 2.417

d = 0.41 m

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An Atwood machine consists of two masses, mA = 6.8 kg and mB = 8.0 kg , connected by a cord that passes over a pulley free to ro
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To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.

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\sum F = m_b a

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T_B-T_A=I\frac{a}{R^2_0}

Replacing the values previously found,

(m_Bg-m_Ba )-(m_Ag-m_Aa )=I\frac{a}{R^2_0}

(m_B-m_A)g-(m_B+m_A)a=I\frac{a}{R^2_0}

a = \frac{(m_B-m_A)g}{\frac{I}{R_0^2}+(m_B+m_A)}

a = \frac{(m_B-m_A)g}{\frac{MR^2_0^2/2}{R_0^2}+(m_B+m_A)}

a =\frac{(m_B-m_A)g}{\frac{M}{2}+(m_B+m_A)}

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a =\frac{(8-6.8)(9.8)}{\frac{0.8}{2}+(8+6.8)}

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PART B) Ignoring the moment of inertia the acceleration would be given by

a' =\frac{(m_B-m_A)g}{(m_B+m_A)}

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a' = 0.7945

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\%error = \frac{a'-a}{a}*100

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8 0
3 years ago
A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. What does th
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Answer:

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4 0
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A traveling wave has displacement given by y(x,t)=(2.0cm)×cos(2πx−4πt), where x is measured in cm and t in s. what is the speed
quester [9]

Answer:

v = 2 cm/s

Explanation:

The equation of the wave is

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Where,

x is measured in cm

t in s

A more general formula for this equation would be

y(x,t)   =  A*cos(k*x−ω*t)

Where,

A = amplitude.

k = the wavenumber

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The velocity of the wave corresponds to

v = ω/k

v = 4π / 2π = 2 cm/s

v = 2 cm/s

8 0
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