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PtichkaEL [24]
3 years ago
5

A. How long (in ns) does it take light to travel 1.0 m in a vacuum?

Physics
1 answer:
suter [353]3 years ago
4 0

Answer:

a) 3.33 ns

b) Water distance = 0.75 m

Glass distance = 0.66 m

Diamond distance = 0.41 m

Explanation:

We take the speed of light, c = m/s.

Speed = distance/time

Time = distance/speed

a)

t=\dfrac{1}{3.0\times10^{8}}=3.33\times10^{-9}

t = 3.33 ns

b)

Refractive index, n = speed of light in vacuum / speed of light in medium

n=\dfrac{c}{s}

s=\dfrac{c}{n}

d=s\times t

d=\dfrac{c}{n}\times \dfrac{1}{c}

d=\dfrac{1}{n}

Thus, the distance traveled in the same time is numerically equal to the reciprocal of the refractive index.

For water n = 1.333

d = 1/1.333 = 0.75 m

For glass n = 1.517

d = 0.66 m

For diamond n = 2.417

d = 0.41 m

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aivan3 [116]

Answer:

Explanation:

Given that,

Initial angular velocity is 0

ωo=0rad/s

It has angular velocity of 11rev/sec

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wi=22πrad/sec

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θ=30revolution

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θ=60πrad

Final angular velocity is

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a. Angular acceleration(α)

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α=21.26 rad/s²

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α=21.26/2π

α=3.38rev/sec

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60π=½(36π+22π)t

60π×2=58πt

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t=2.07seconds

c. Time to reach 11rev/sec

wf=wo+αt

22π=0+21.26t

22π=21.26t

Then, t=22π/21.26

t=3.251seconds

d. Number of revolution to get to 11rev/s

∆θ= ½(wf+wo)•t

∆θ= ½(0+11)•3.251

∆θ= ½(11)•3.251

∆θ= 17.88rev.

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