Answer:
pKa = 4.89.
Explanation:
We can solve this problem by using the <em>Henderson-Hasselbach equation</em>, which states:
pH = pKa + log ![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
In this case [A⁻] is the concentration of sodium benzoate and [HA] is the concentration of benzoic acid.
We <u>input the given data</u>:
4.63 = pKa + log 
And <u>solve for pKa</u>:
pKa = 4.89
2Al+3Cl2==>2AlCl3
(4mol Al)(2 mol AlCl3/2 mol Al)=4 mole AlCl3
<span>0.001 M Ba(OH)2 has a higher pH</span>
3Fe(s) + 4H2O(l) — 1Fe3O4(s) + 4H2(g)
Answer:
0.72 mole of oxygen would produce 320.4 kJ of heat.
Explanation:
CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ
According to the equation,
2 moles of O₂ produces 890 kJ of heat
So, 0.72 moles of O₂ will produce:
Therefore, 0.72 moles of oxygen would produce 320.4 kJ of heat.
