All categories

3 years ago

4. What is the main hydrocarbon component of natural gas? A. ethane

Chemistry

2 answers:

KIM [24]3 years ago

7 0

Answer:

Q.4) C. Methane

Q.7) A. False

Q.8) A. True

777dan777 [17]3 years ago

4 0

Tryna boost my score for college chemistry could you give me the brainiest and a thanks? Hope you find your answer your looking for!

You might be interested in

An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The

Nataly_w [17]

Answer:

Explanation:

5 0

3 years ago

When an action force occurs, the reaction force is always Question 6 options: A.in the same direction as the action force. B.app

Mrac [35]

D. 100%, extremely sure. Because Newton's 3rd law states every force has an equal and opposite reaction.

7 0

2 years ago

Read 2 more answers

Into how many peaks will each proton shown in red be split

Tamiku [17]

The proton has two adjacent protons, so it splits into three peaks, a triplet. The proton has three adjacent protons, so it splits into four peaks, a quartet.

8 0

3 years ago

Polonium -210 decays once before it becomes a stable atom. What is that stable atom?

ycow [4]

Answer:

A. 206 Pb

Explanation:

5 0

3 years ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0

2 years ago