Initial volume of mercury is
V = 0.1 cm³
The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.
Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³
The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
= (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
= 4.5 cm
Answer: 4.5 cm
Answer:
1,200 watts
Explanation:
1 watt = 1 Joule (J) of work / second
So, 3600 Joules of work / 3 seconds is:
3600 J / 3 seconds = 1,200 watts
Jake was playing making a paper airplane, after making he kept it on the table and went to have food.
Suddenly his brother saw the plane and threw it in the air, The airplane kept flying for about 3m/s and it hit his mother and due to the force the plane stopped.
{kept in on the table>rest
brother threw the plane>moving
it hit his mother>force that stopped it}
(mark me brainliest if you're satisfied with my answer)
Answer:
Pilots depend on the precision of INSTRUMENT LANDING SYSTEMS to guide them when they have limited visibility.
Explanation:
A pilot is a professionally trained individual that has the ability to control an aircraft following directions from a flight control.
Instrument landing system is a guidance system that makes available an instrument based procedures for guiding the pilot of an aircraft to approach and land safely. This system guides the pilot during unfavorable conditions such as low visibility through the use of radio signals.
There are two types of guidance provided by this system:
-> Lateral guidance subsystem and
-> Vertical guidance subsystem.
Lateral guidance subsystem prevents the aircraft approaching a runway to shift laterally from the path recommended.
Vertical guidance subsystem prevents the aircraft approaching a runway to shift laterally from the recommended path.
