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Ivan
3 years ago
14

What is the GCF of 3 , 12 , and 18

Mathematics
2 answers:
Stella [2.4K]3 years ago
3 0
Answer is 3 because it is the greatest common factor
mamaluj [8]3 years ago
3 0
The GCF is 3 because the lowest number is 3 and its only factors are 1 and 3. 12 and 18 also have a factor of 3 so that would be that greatest common factor
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PLEASE HURRY!!
Arisa [49]

Answer:

Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.

Step-by-step explanation:

The distance of Tasha's balloon from the town is represented by the function y = 8x+ 20 ............. (1)

Where y is the distance in miles from the town and x represents the time of fly in hours.

So, at the start of the journey i.e. at x = 0, y = 20 miles {From equation (1)} from the town.

Again, Tasha's balloon is traveling at a rate of 8 miles per hour.

Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.

So, Henry's balloon traveling with the speed of \frac{48 - 30}{2} = 9 miles per hour.

Therefore, Henry's balloon was farther from the town at the beginning i.e. 30 miles from the town. And Henry's balloon traveled more quickly i.e at the rate of 9 miles per hour. (Answer)

8 0
3 years ago
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sammy [17]

Answer:

Step-by-step explanation:

5 0
2 years ago
3p - 5 = 19<br> Answer when solved??
lianna [129]

Answer: P=8

Step-by-step explanation:

3p-5=19

U turn -5 to +5

Then u add 5 to both sides, -5 and 19

3p-5=19

+5=+5

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3p=24

Because 19 plus 5 is 24

Now u have to get the variable by itself by dividing 3 on both sides of the equal sign 3p and 24

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3 0
3 years ago
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Elodia [21]

Answer:

$2.56

Step-by-step explanation:

If you multiply 12.82 by .20, you would get 2.564. Then you just round it up and the answer you get is $2.56. Hope this helps!

8 0
3 years ago
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babunello [35]

Step-by-step explanation:

remember the domain is the interval or set of valid input (x) values. the range is the interval or set of the valid result (y) values.

so, the given domain tells us the interval to look at.

what are the functional values of the function between 0 and 50 ?

since the function is continuous (there are no gaps) in this interval, we can safely assume that all values between f(0) and f(50) are valid y values.

f(0) = 4×0 + 5 = 5

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so, the range is 5 <= y <= 205

3 0
3 years ago
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