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Dovator [93]
3 years ago
6

The picture below shows Lake Jackson in Florida

Physics
1 answer:
nikklg [1K]3 years ago
4 0
The reason why Lake Jackson disappeared is A. opening of a sinkhole.
Pollution, high atmospheric temperature, and absorption of water by the land aren't enough for an entire lake to disappear, however, a sinkhole may contribute to that. There are two major depressions (sinkholes) in this lake in Florida, and they even have their own names - Porter Sink and Lime Sink. 
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The Reynolds number, rho VD/mu, is a very important parameter in fluid mechanics. Verify that the Reynolds number is dimensionle
Agata [3.3K]

Answer:

Re = 1 10⁴

Explanation:

Reynolds number is

         Re = ρ v D /μ

The units of each term are

       ρ = [kg / m³]

       v = [m / s]

      D = [m]

      μ = [Pa s]

The pressure

      Pa = [N / m²] = [Kg m / s²] 1 / [m²] = [kg / m s²]

      μ = [Pa s] = [kg / m s²] [s] = [kg / m s]

We substitute the units in the equation

      Re = [kg / m³] [m / s] [m] / [kg / m s]

      Re = [kg / m s] / [m s / kg]

      RE = [ ]

Reynolds number is a scalar

Let's evaluate for the given point

Where the data for methane are:

viscosity       μ = 11.2 10⁻⁶ Pa s

the density  ρ = 0.656 kg / m³

       D = 2 in (2.54 10⁻² m / 1 in) = 5.08 10⁻² m

       Re = 0.656 4 2 5.08 10⁻² /11.2 10⁻⁶

       Re = 1.19 10⁴

4 0
3 years ago
After a massive-star supernova, what is left behind?.
scoray [572]

Answer: A <u>Nebula </u>is left behind. A spectacular explosion in which a star ejects most of its mass in a violently expanding cloud of debris.

Hope this helps!

8 0
2 years ago
Two cars - Car A and Car B - drive in the same direction down a street. Car B is traveling at 30 m/s. Car A is traveling 20 m/s.
Darina [25.2K]

Answer:derp

Explanation:

8 0
2 years ago
A temperature of 20°c is equivalent to approximately
Yanka [14]
C would be your answer
8 0
3 years ago
Read 2 more answers
The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9
Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

P=\frac{90I}{I^2+I+9}

now differentiating the above equation with respect to Intensity 'I' we get

\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}

Now for the maxima \frac{dP}{dI}=0

thus,

0=\frac{-90I^2+810)}{(I^2+I+9)^2}

or

-90I^2+810=0

or

I^2=\frac{810}{90}

or

I^2=9

or

I = 3

thus, <u>for the value of intensity I = 3, the P is maximum</u>

at I = 3

P=\frac{90\times3}{3^2+3+9}

or

P=\frac{270}{21}

or

P=12.85

5 0
3 years ago
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