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Alenkinab [10]
3 years ago
15

A 0.30-kg flying pig toy is attached to the ceiling with a string. When the pig’s wings flap, it moves at a constant speed of �

= 2.00 m/s in a horizontal circle of radius � = 0.25 m. Find the angle � the string makes with the vertical.

Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

58.5 deg

Explanation:

v = mass of the pig toy = 0.30 kg

v = speed of the toy = 2 m/s

r = radius of the circle = 0.25 m

\theta = Angle of the string with the vertical = ?

T = Tension force in the string

Using equilibrium of force in vertical direction

T Cos\theta = mg                                     eq-1

Along the horizontal direction, the component of tension force provides the necessary centripetal force, hence

T Sin\theta = \frac{mv^{2}}{r}                                  eq-2

Dividing eq-2 by eq-1

\frac{T Sin\theta}{T Cos\theta} = \frac{\frac{mv^{2}}{r}}{mg}

tan\theta= \frac{v^{2}}{rg}

tan\theta= \frac{(2)^{2}}{(0.25)(9.8)}

tan\theta = 1.63

\theta = 58.5 deg

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