The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge.
E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.
So E=(k*q)/r²
When we input the numbers we get that electric field E of a point chage q is:
E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B.
Answer:
1066.67 m
Explanation:
Given:
v₀ = 96 km/h = 26.67 m/s
v = 48 km/h = 13.33 m/s
Δx = 800 m
Find: a
v² = v₀² + 2aΔx
(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)
a = -0.333 m/s²
Given:
v₀ = 26.67 m/s
v = 0 m/s
a = -0.333 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx
Δx = 1066.67 m
Round as needed.
<span>One type of substance is a >>element<<, which contains only one type of atom.</span>
Answer:
D. TA < TB
Explanation:
From general gas equation, we know that:
PV = nRT
PV/R = nT
where,
P = pressure of gas
V = volume of gas
R = General gas constant
T = temperature of gas
n = no. of moles of gas
<u>FOR CYLINDER A</u>:
PV/R = (nA)(TA) _____ eqn (1)
<u>FOR CYLINDER B</u>:
PV/R = (nB)(TB) _____ eqn (2)
Because, Pressure, Volume are constant for both cylinders.
Comparing eqn (1) and (2)
(nA)(TA) = (nB)(TB)
It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.
nA = 2(nB)
using this in eqn:
2(nB)(TA) = (nB)(TB)
TA = (1/2)(TB)
<u>TA = 0.5 TB</u>
Therefore it is clear that the correct option is:
<u>D. TA<TB</u>
Answer:
Explanation:
(a) For the calculation of the Electric field we use
(b) The capacitance is calculate by using the expression
(c) Finally, the charge on each plate is
I hope this is useful for you
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