A form of energy produced my a machine

¿Que atomo gana el electron?

antoniya [11.8K]

Answer:

anion

Explanation:

3 0

3 years ago

A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. Ho

Anestetic [448]

The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

= 0.2× 25×3/0.75 ×1

= 15/0.75

Vb ( x mL) = 20 mL

Learn more here:

brainly.com/question/23631409

8 0

2 years ago

1. If a solution containing 48.99 g of mercury(II) perchlorate is allowed to react completely with a solution containing 8.564 g

Vitek1552 [10]

1. Chemical eqn:

Hg(ClO4)2 + Na2S -> HgS + 2NaClO4

mercury perchlorate has a molar mass of 399.5g/mol (1d.p) and for Na2S it is 78.0g/mol (1d.p.)

no. of moles of mercury perchlorate= 48.99÷399.5= 0.12263mol(5s.f.)

no. of moles of Na2S= 8.564÷78.0= 0.10979mol ( 5s.f.)

so no. of moles of Hg(ClO4)2/ no. of moles of Na2S= 1/1 according to the eqn

so no. of moles of Hg(ClO4)2 needed if all Na2S is used up is 1/1×0.10979= 0.10979 mols

since no. of moles of mercury perchlorate needed < no. of moles of it provided, it is in excess and Na2S is the limiting factor.

since HgS is a solid and NaClO4 is aqueous, solid ppt formed will only be HgS.

no. of moles of HgS/ no. of moles of NaClO4= 1/1

no. of moles of HgS produced= 0.10979mols

molar mass of HgS= 232.7g/mol 1d.p.

grams of solid produced= 232.7×0.10979= 25.5g (3s.f.)

2. reactant in excess is Hg(ClO4)2,

no. of excess moles= 0.12263-0.10979= 0.01284mols

grams of excess reactant= 0.01284×399.5= 5.13g (3s.f.)

3 0

3 years ago

Convert the following to grams, a. 0.100 moles of CO2

Svetlanka [38]

.100 mol CO2 x $\frac{44.01 g}{1 mol}$
using the values of the periodic you first add the masses of C (12.01g) and O (there are two so it'll be 32.00g). That value will give the mass of 1mole of CO2.

I hate to do this, but
https://youtu.be/Pft2CASl0M0 is a link to a mr andersen video. I dislike watching these cause this is what my teacher uses instead of actually having to teach herself.

3 0

3 years ago

Which subatomic particle has the least mass? electron proton neutron nucleus

Andreas93 [3]

the answer is electrons

4 0

3 years ago

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