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andrew-mc [135]
2 years ago
7

Which elements are known as the transition metals

Chemistry
2 answers:
tresset_1 [31]2 years ago
7 0

These are the transition metals that I believe you are needing. Happy studying!

Scandium

Titanium

Vanadium

Chromium

Manganese

Iron

Cobalt

Nickel

Copper

Zinc

Yttrium

Zirconium

Niobium

Molybdenum

Technetium

Ruthenium

Rhodium

Palladium

Silver

 

Cadmium

Hafnium

Tantalum

Tungsten

Rhenium

Osmium

Iridium

Platinum

Gold

Mercury

Rutherfordium

Dubnium

Seaborgium

Bohrium

Hassium

Meitnerium

Ununnilium

Unununium

Ununbium


melisa1 [442]2 years ago
5 0

Groups IVB–VIII, IB, and IIB, or 4–12

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IceJOKER [234]

Answer:

A

Explanation:

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2 years ago
Which of the following molecules would exhibit only London forces?a)CH4, BH3, and CCl4b)H2O, NH3, and CCl4c)PH3, NH3, and CCl4
Alex787 [66]

Answer:

a)CH₄, BH₃, and CCl₄

Explanation:

<u>London dispersion forces:- </u>

The bond for example, in the molecule is F-F, which is non-polar in nature because the two fluorine atoms have same electronegativity values.

The intermolecular force acting in the molecule are induced dipole-dipole forces or London Dispersion forces / van der Waals forces which are the weakest intermolecular force.

Out of the given options, H₂O , NH₃ exhibits hydrogen bonding which is:-

<u>Hydrogen bonding:- </u>

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Thus option B and C rules out.

<u>Hence, the correct option which represents the molecules which would exhibit only London forces is:- a)CH₄, BH₃, and CCl₄</u>

4 0
3 years ago
How many moles of oxygen must be placed
Annette [7]

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The variables given are Pressure, volume  and temperature.

Explanation:

Given:

P = 2 atm

V = 3 litres

T = 25 degrees or 298.15 K by using the formula 25 + 273.17 = K

R  = 0.082057 L atm/ mole K

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The equation used is of Ideal Gas law:

PV = nRT

n = \frac{PV}{RT}

Putting the values given for oxygen gas in the Ideal gas equation, we get

n = \frac{2 x 3}{0.082157 x 298.15}

  = 0.24

Thus, from the calculation using Ideal Gas law it is found that 0.24 moles of oxygen must be placed in a container.

Ideal gas law equation is used as it tells the relation between temperature, pressure and volume of the gas.

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