Answer:
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Explanation:
Answer: normal fault
A fault refers to a planar or curved fracture in the rocks of the Earth crust, in which compressional or tensional forces results in the displacement of the rock on the opposite side of the fracture. Fault may vary in the length of the fracture. A normal fault is a fault in which the hanging wall of the rock moves downward to the footwall. It occurs when the two blocks of rock are separated apart by the tensional forces.
On the basis of the above information, the normal fault is the fault that should be found by the geologists in the rock.
Answer:
K = 2.7x10⁻⁵ at 25ºC
Explanation:
A way to write Arrhenius equation is:
ln K = - Ea/R × (1/T) + lnA
If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:
Y = -13815X +35.817
R² = 0.9927
(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)
Your slope is -13815
-13815K = - Ea/R
-13815K×8.314J/molK = 114858J/mol = Ea
And your intercept =
lnA = 35.817
A = 3.59x10¹⁵
Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):
Y = -13815X +35.817
Y = -13815(1/298.15K) +35.817
Y = -10.5187
lnK = -10.5187
<h3>K = 2.7x10⁻⁵ at 25ºC</h3>
Its<span> a nuclear process used for determining the concentrations of elements in a cast amount of materials.</span>
