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storchak [24]
4 years ago
12

A horizontal pull A pulls two wagons over a horizontal frictionless floor, the first wagon is 500N, the second is 2000 N. The te

nsion in the light horizontal rope connecting the wagons is.
help explain your answer,
Physics
1 answer:
MrMuchimi4 years ago
5 0
<span>The force will be zero if the wagons are moving at a constant speed (i.e. not accelerating), as there is no frictional force to overcome. If the wagons are accelerating, the force will be proportional to the acceleration, and 20% of the force applied by A.</span>
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A bat emits a sound at a frequency of 30.0 kHz as it approaches a wall. The bat detects beats such that the frequency of the ech
Alex

Answer:

The speed of the bat is 5.02 m/s.

Explanation:

Given that,

Frequency = 30.0 kHz

Frequency of echo = 900 Hz

We need to calculate the frequency

Using formula of beat frequency

f_{b}=f_{1}-f_{2}

Put the value into the formula

900=f_{1}-30\times10^{3}

f_{1}=900+30000

f_{1}=30900\ Hz

We need to calculate the speed of the bat

Using Doppler equation

f_{apr}=f\times(\dfrac{v_{sound}+v_{observer}}{v_{s}-v_{source}})

Put the value into the formula

30900=30000\times(\dfrac{340+v_{bat}}{340-v_{bat}})

\dfrac{30900}{30000}=\dfrac{340+v_{bat}}{340-v_{bat}}

1.03=\dfrac{340+v_{bat}}{340-v_{bat}}

340\times1.03-340=v_{b}+1.03v_{b}

10.2=2.03v_{bat}

v_{bat}=\dfrac{10.2}{2.03}

v_{bat}=5.02\ m/s

Hence, The speed of the bat is 5.02 m/s.

6 0
3 years ago
A bicyclist increases her speed from 4.0 m/s to 6.0 m/s. The combined mass of the bicyclist and the bicycle is 55 kg. How much w
11Alexandr11 [23.1K]
Kinetic energy of the horse and rider = 1/2 (mass) (speed)²

At 4.0 m/s :  KE = 1/2 (55kg) (4 m/s)²  =  440 joules

At 6.0 m/s :  KE = 1/2 (55kg) (6 m/s)²  =  990 joules

She increased the kinetic energy of herself and her vehicle by 550 joules,
so she must have put at least that much work into it.
4 0
4 years ago
Read 2 more answers
Explain how forces of attraction and repulsion exist within an atom. describe how an electric charge is developed by friction or
dalvyx [7]

There are three kinds of forces within the atom:

  i) Electromagnetic force of attraction between the electrons and protons

  ii) Electromagnetic force of repulsion between the protons or weak nuclear force

  iii) Strong nuclear force between the electrons and protons

<h3>What is nuclear force?</h3>

The electromagnetic force of attraction:

  • Electrons circle in the orbits above the nucleus. There exists an electromagnetic force of pull between the electrons and protons. That’s why electrons do not depart the atom.

Weak nuclear force:

  • It is an electromagnetic significance of revulsion between the protons in the nucleus of the atoms.

Strong nuclear force:

  • This force is strongest from all the fundamental details and exists between the protons and neutrons in the nucleus of an atom. This pressure overcomes the weak nuclear force and does not allow protons to stray out.

To learn more about nuclear force, refer to:
brainly.com/question/8695581

#SPJ4

3 0
2 years ago
Which statements about acceleration are true?
larisa86 [58]
C is the correct answer, hope it helps
5 0
4 years ago
Read 2 more answers
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that
Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

T = \frac{t}{n}

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

T = \frac{135\ s}{98}

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

T = 2\pi \sqrt{\frac{l}{g}}

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}

<u>g = 11.2 m/s²</u>

3 0
3 years ago
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