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yan [13]
4 years ago
13

A 4.5 kg mass is accelerated at 40 m/s/s what is the force that was applied

Physics
1 answer:
cestrela7 [59]4 years ago
8 0

Answer:

180 N

Explanation:

Use Newton's second law, F = ma.

m = 4.5 kg; a = 40 m/s/s

F = (4.5)(40) = 180 N

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Explanation:

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A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done
Alexxandr [17]
  • Force=150N
  • Angle=60°
  • Displacement=50m

\boxed{\sf W=Fscos\Theta}

\\ \sf\longmapsto W=150(50)cos 60

\\ \sf\longmapsto W=7500\times \dfrac{1}{2}

\\ \sf\longmapsto W=3750J

6 0
3 years ago
A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest
enyata [817]

Answer:

v = 2,425 m / s

Explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

           Em₀ = U = m g y

lowest point

          Em_{f} = K = ½ m v²

         Em₀ = Em_{f}

        mg y = ½ m v²

        v = √ 2gy

let's calculate

        v = √ (2 9.8 0.3)

        v = 2,425 m / s

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3 years ago
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