The United States spends over $20 billion a year on space exploration through NASA. Do you think that this has been worth the co
1 answer:
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Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
This is an incomplete question, here is a complete question.
The air in the cylinder with a piston has a volume of 220 mL and a pressure of 650 mmHg.
If the pressure inside the cylinder increases to 1.6 atm, what is the final volume, in milliliters, of the cylinder?
Answer : The final volume of the cylinder is, 117.6 mL
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
or,
where,
= initial pressure of gas = 650 mmHg = 0.855 atm (1 atm = 760 mmHg)
= final pressure of gas = 1.6 atm
= initial volume of gas = 220 mL
= final volume of gas = ?
Now put all the given values in the above equation, we get:
Therefore, the final volume of the cylinder is, 117.6 mL
Answer:
b) Springs oscillate with the same frequency,
Explanation:
expression for frequency of vibration of mass hanging from a spring is given as follows
f =
k is force constant of spring and m is mass vibrating .
In the present case, if mass stretches the spring by x and remains balanced
mg = k x
g and x are same for both cases
will also be same for both cases .
Hence frequency of vibration will also be same for both the balls .