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earnstyle [38]
4 years ago
9

Solve for m: (y_1 - y_2) = m(x_1 - x_2)

Mathematics
1 answer:
Mashutka [201]4 years ago
5 0
y_1-y_2=m(x_1-x_2)\\
m=\dfrac{y_1-y_2}{x_1-x_2}
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Find the output for the graph<br> y = -6x + 25<br> when the input value is 3.<br> =<br> y = [?]
avanturin [10]

<u><em>Answer</em></u>

x=\frac{11}{3}

<u><em>Explanation</em></u>

Based on the given conditions, formulate:: y=3

Substitute y=3 into y=-6x+25 :: 3=-6x+25

Rearrange variables to the left side of the equation: 6x=25-3

Calculate the sum or difference: 6x=22

Divide both sides of the equation by the coefficient of variable: x=\frac{22}{6}

Cross out the common factor: x=\frac{11}{3}

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Simplify the expression 5 + (15 + x).<br> A. 5x + 20<br> B. x + 20<br> C. x + 5<br> D. x+ 15
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3 years ago
Graphing rational functions. I need help asap!!!!
Anastaziya [24]

Answer:

1.  

Vert. asymptote: x = {-3, 2}

Horiz. asymptote: y = 0

x-int: None

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c. f(x) = 0: x = {0, -1/2}

d. The graph has no hole at (-2, 4)

Question 4.

a. Vert. asymptote: x = {-2, 2}

b. f(x) = 0: x = {0, -1/2}

c. Horizontal asymptote: y = 2

d. The graph has no hole

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6 0
3 years ago
Need help ASAP!!! Please help
cestrela7 [59]
The range of a function is the set of numbers used as y-coordinates.

Let's look at the y-coordinates of the points in the graph.
There are points in the graph with all y-coordinates greater than -3.
There are points in the graph with all y-coordinates less then -3.
At exactly -3, there is no point on the graph with that y-coordinate.
We expect the graph to behave as it is shown above 7 and below -7, so the only value excluded from the y-coordinates is -3.

Answer: B. All real numbers except -3
8 0
4 years ago
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