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Elan Coil [88]
3 years ago
5

What is kinetic energy?

Engineering
2 answers:
Aleksandr [31]3 years ago
8 0

Answer:

<em>Kinetic</em><em> </em><em>Energy</em><em> </em>is a type of energy which a body possesses by virtue of being in motion.

<u>OR</u>

It's the energy of mass in motion.

<h3 /><h3>Hope it helps!!</h3><h3><em>Please</em><em> </em><em>mark me as the brainliest</em><em>!</em><em>!</em><em>!</em></h3>

<em>Thanks</em><em>!</em><em>!</em><em>!</em><em>!</em>

disa [49]3 years ago
3 0

Answer:

kinetic energy means energy which a body possesses by virtue of being in motion

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Which of the following factors does not promote safety in the shop?
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A circular hoop sits in a stream of water, oriented perpendicular to the current. If the area of the hoop is doubled, the flux (
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Answer:

The flux (volume of water per unit time) through the hoop will also double.

Explanation:

The flux = volume of water per unit time = flow rate of water through the hoop.

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This means that

Flow rate = AV

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V is the velocity of the water through the hoop

This flow rate = volume of water per unit time = Δv/Δt =Q

From all the above statements, we can say

Q = AV

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3 years ago
What is the next measurement after 2' -6" on the architect's scale?
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3 years ago
At steady state, a reversible refrigeration cycle discharges energy at the rate QH to a hot reservoir at temperature TH, while r
ludmilkaskok [199]

Answer:

a) COP_{R} = 25.014, b) T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)

Explanation:

a) The coefficient of performance of a reversible refrigeration cycle is:

COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}

Temperatures must be written on absolute scales (Kelvin for SI units, Rankine for Imperial units)

COP_{R} = \frac{275.15\,K}{286.15\,K-275.15\,K}

COP_{R} = 25.014

b) The respective coefficient of performance is determined:

COP_{R} = \frac{Q_{L}}{Q_{H}-Q_{L}}

COP_{R} = \frac{8.75\,kW}{10.5\,kW-8.75\,kW}

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But:

COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}

The temperature at hot reservoir is found with some algebraic help:

COP_{R} \cdot (T_{H}-T_{L})=T_{L}

T_{H}-T_{L} = \frac{T_{L}}{COP_{R}}

T_{H} = T_{L}\cdot \left(1+\frac{1}{COP_{R}}  \right)

T_{H} = 273.15\,K \cdot \left(1+\frac{1}{5}  \right)

T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)

8 0
3 years ago
Read 2 more answers
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