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3241004551 [841]
3 years ago
12

2.(10 pts)A proposed engine cycle employs an ideal gas and consists of the following sequence of transformations; a) Isothermal

compression at 300 o K from a pressure of 1bar to a pressure of 30bar b) Constant pressure heating to a temperature of 1600 o K. c) Isothermal expansion at 1600 o K to the original pressure of 1 bar. d) Constant pressure cooling to a temperature of 300 o K to complete the cycle An ideal regenerator connects d) to b) so that the heat given up in d) is used for the heating in b). For an engine using a kilamole of gas find the net work in kJ and the thermal efficiency. You may assume C p

Engineering
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Check the explanation

Explanation:

For ideal regeneration heat loss in cooling aqual to heat gain in compression so temperature Tb=Td as  can be seen in the step by step solution in the attached images below.

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A steel bar 100 mm long and having a square cross section 20 mm x 20 mm is pulled in
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Answer:

222.5 Gpa

Explanation:

From definition of engineering stress, \sigma=\frac {F}{A}

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Also, engineering strain, \epsilon=\frac {\triangle l}{l} where l is original area and \triangle l is elongation

We also know that Hooke's law states that E=\frac {\sigma}{\epsilon}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}

Since A=20 mm* 20 mm= 0.02 m*0.02 m

F= 89000 N

l= 100 mm= 0.1 m

\triangle l= 0.1 mm= 0.1\times 10^{-3} m

By substitution we obtain

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Answer:

COP(heat pump) = 2.66

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Explanation:

Given:

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COP(Theoretical maximum) = 293 / (293 - 273)

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ddddddddddddddddddddddddddddd

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