Here is the formula that will help to solve this task: <span>P1/T1 = P2/T2 </span> <span> Keep in mind that value 20 C is an equivalent to 293 K. If you have to make new pressure</span><span> 12.4 atm, the given temperature must be changed intor 284K. Therefore: </span>The correct answer is B)At 15.4 atm, T2 would have to be 353 K (which is 120 C) As you can see, these options are not suitable: <span>At 16.6 atm, T2 would have to be 381 K </span> <span>At 18.6 atm, T2 would have to be 426 K</span>
Gay-Lussac explained the relation between the temperature and the pressure of the gas. Gay-Lussac's law states that: "At constant volume, the pressure of the gas is directly proportional to its temperature in kelvin" This means that: P/T = constant
Based on this: P1/T1 = P2/T2 where: P1 is the initial pressure = 13 atm T1 is the initial temperature = 20 + 273 = 293 degree kelvin P2 is the final pressure that we need to calculate T2 is the final temperature = 102 + 273 = 375 degree kelvin
Substitute with the givens to get the final pressure as follows: 12/293 = P2/375 4500 = 293 P2 P2 = 15.4 atm
Based on the above calculations, the correct choice is: B.15.4 atm
