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DENIUS [597]
4 years ago
10

What happens to the number of waves when you decrease the wavelength?

Chemistry
1 answer:
Keith_Richards [23]4 years ago
6 0

C

Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.

Explanation:

The energy of a wave is given by the formula;

E= hf

Whereby;

E = energy

h = Plank’s constant

f = frequency

Remember that f can be also represented as;

¹/ λ

Whereby;

λ = wavelength

Wavelength and frequency are therefore inversely proportional.

Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.

Learn More:

For more on frequency and wavelength of waves check out;

brainly.com/question/13451801

brainly.com/question/9501542

brainly.com/question/14068647

brainly.com/question/12924624

brainly.com/question/10955773

#LearnWithBrainly

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onvert the value of Kc to a value of Kp for the following reaction: N2(g)+3H2(g)⇌2NH3(g) Kc = 0.50 at 400 °C.
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Answer:

K_p= 0.00016

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

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Kc is the molar equilibrium constant

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T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

N_2_{(g)}+3H_2_{(g)}\rightleftharpoons2NH_3_{(g)}

Given: Kc = 0.50

Temperature = 400^oC=[400+273]K=673K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(3+1) = -2

Thus, Kp is:

K_p= 0.50\times (0.082057\times 673)^{-2}

K_p= 0.00016

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3 years ago
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First, you want to extract the negative from -log(x).

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Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

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