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2 years ago

Which statement describes how work and power are similar?

2 answers:

6 0

The statement that describes how work and power are similar is D. you must know time and energy to calculate both.
I am not completely sure though, so I hope this helps. :)

sertanlavr [38]2 years ago

6 0

Which statement describes how work and power are similar?

Answer: Out of all the options shown above the one that best describes how work and power are similar is answer choice A) You must know force and distance to calculate both. The reason being that work equals force X distance and power equals work/time.

I hope it helps, Regards.

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If it takes 50n of force to lift a 450n what is the ma of the machine

otez555 [7]

If the machine is 100% efficient, then its
Mechanical Advantage is (450/50) = 9 .

If the machine is less than 100% efficient,
then the MA is more than 9 .

7 0

3 years ago

A 0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the fo

Troyanec [42]

Impulse = Change in momentum.
The ball was moving with a momentum of 0.45 * 22 = 9.9
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9

3 0

2 years ago

The momentum of an object is determined by the object’s mass and velocity. Which object has more momentum?

Gnesinka [82]

Answer:

You need to give the options but the formula is p=mv

Explanation:

7 0

2 years ago

A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at

yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

$\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)$

Therefore, the work done by the worker in lifting the bucket is given as:

$W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)$

Now, plug in the values given and solve for 'W'. This gives,

$W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J$

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

7 0

2 years ago

Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1360 N. Assume that the play

Alona [7]

Answer:

7.59Ns

Explanation:

Given parameters:

Force = 1360N

Time of contact = 5.85 x 10⁻³s

Unknown:

Impulse = ?

Solution:

The impulse of the ball is given as:

Impulse = Force x time

Impulse = 1360 x 5.85 x 10⁻³ = 7.59Ns

4 0

2 years ago