If 100. mL of 0.400 M Na2SO4 is added to 200. mL of 0.600 M NaCl, what is the concentration of Na+ ions in the final solution? A
1 answer:
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Explanation:
It is given that r = 0.283 nm. As 1 nm = .
Hence, 0.283 nm =
- Formula for coulombic energy is as follows.
where, e = C
=
=
- As 1 eV =
So, 1 J =
Hence, U =
= 8.9 eV
- Also, 1 J =
= kJ/mol
Therefore, U = kJ/mol
=
<u>Answer: </u>The volume of the solution is 85.7 mL
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
We are given:
Molarity of solution = 0.600 M
Given mass of = 12.00 g
We know, molar mass of
Putting values in equation 1, we get:
The rule of significant number that is applied for the problems having multiplication and division:
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.
Hence, the volume of the solution is 85.7 mL