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patriot [66]
3 years ago
14

If 100. mL of 0.400 M Na2SO4 is added to 200. mL of 0.600 M NaCl, what is the concentration of Na+ ions in the final solution? A

ssume that the volumes are additive.
Chemistry
1 answer:
Dmitrij [34]3 years ago
4 0
Na₂SO₄ → 2Na⁺ + SO₄²⁻

c₁(Na⁺)=2c(Na₂SO₄)

n₁(Na⁺)=c₁(Na⁺)v₁=2c(Na₂SO₄)v₁

NaCl → Na⁺ + Cl⁻

c₂(Na⁺)=c(NaCl)

n₂(Na⁺)=c₂(Na⁺)v₂=c(NaCl)v₂

n(Na⁺)=n₁(Na⁺)+n₂(Na⁺)=2c(Na₂SO₄)v₁+c(NaCl)v₂

v=v₁+v₂

c(Na⁺)=n(Na⁺)/v={2c(Na₂SO₄)v₁+c(NaCl)v₂}/(v₁+v₂)

c(Na⁺)={2*0.400*0.1+0.600*0.2}/(0.1+0.2)=0.667 mol/L

c(Na⁺)=0.667M
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The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

\frac{dA}{dt}= kA

\Rightarrow \frac{dA}{A}=kdt

Integrating both sides

ln A= kt+c₁

\Rightarrow A= e^{kt+c_1}

\Rightarrow A=Ce^{kt}         [e^{c_1}=C]

The initial condition is A(0)= A₀,

\therefore A_0=Ce^{0.k}

\Rightarrow C=A_0

\therefore A=A_0e^{kt}.........(1)

Given that the Pb_{209}  has half life of 3.3 hours.

For half life A=\frac12 A_0 putting this in equation (1)

\frac12A_0=A_0e^{k\times3.3}

\Rightarrow ln(\frac12)= 3.3k     [taking ln both sides, ln \ e^a=a]

\Rightarrow k=\frac{ln \frac12}{3.3}

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

\therefore 0.2=1e^{(-0.21)\times t}

\Rightarrow e^{-0.21t}=0.2

\Rightarrow -0.21t= ln(0. 2)

\Rightarrow t= \frac{ln (0.2)}{-0.21}

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0
3 years ago
Sound is a _____ Wave because it cannot travel without a medium.
lord [1]

Answer:

It is a longitudinal wave.

Explanation:

Hope this helped.

5 0
3 years ago
Read 2 more answers
Passive prostheses are:
Len [333]

Passive prostheses are self-regulating, as shown in the first answer option.

We can arrive at this answer because:

  • Passive prostheses are devices used to replace parts of the body that were lost by an incident.
  • These prostheses are very useful to establish balance or the aesthetics of the body, but they have no articulations and no movement mechanism, being static.

This limitation allows passive prostheses not to need external regulation and to be self-regulated by fitting the body parts.

You can find more information about articulations and their effects on the link:

brainly.com/question/5847359?referrer=searchResults

5 0
2 years ago
Read 2 more answers
Write the equation for the reaction described: A solid metal oxide, Ag2O, and hydrogen are the products of the reaction between
Harlamova29_29 [7]

Answer:

2Ag + H2O -----> Ag2O + 2H

Explanation:

2Ag + H2O -----> Ag2O + 2H is the equation of the reaction between metal and steam. Silver reacts with water (steam) forming silver oxide and hydrogen gas. When the metals react with steam it produces the solid metal oxide and hydrogen gas. On the surface o metals, a protective layer of aluminium oxide is formed that keeps water away from the metal so we can say that silver oxide and hydrogen are formed from the reaction of silver metal and steam.

8 0
3 years ago
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kolbaska11 [484]

Answer:

njjii

Explanation:

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