A reaction in which bonds are created is usually associated with the Release of energy.
What are the various types of bonds?
There are three sorts of bonds:
1. Electrovalent or electrovalent bond
2. chemical bond
3. dative bond
Electrovalent or electrovalent bond are formed when one or more electrons are transferred from one atom to another.
Covalent bonds are formed when the atoms during a molecule share an equal number of electrons.
A dative bond is one in which both electrons in a shared pair come from the same atom.
Now, atoms tend to stabilize once they form chemical bonds, releasing energy within the process. Energy is released because there's a higher level of stability associated with a low energy level.
Hence, a reaction in which bonds are created is usually associated with the release of energy.
To know more about chemical bonds go to the given link:
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Answer:
9.36
Explanation:
Sodium formate is the conjugate base of formic acid.
Also,
![K_a\times K_b=K_w](https://tex.z-dn.net/?f=K_a%5Ctimes%20K_b%3DK_w)
for sodium formate is ![K_b=\frac {K_w}{K_a}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%20%7BK_w%7D%7BK_a%7D)
Given that:
of formic acid = ![1.8\times 10^{-4}](https://tex.z-dn.net/?f=1.8%5Ctimes%2010%5E%7B-4%7D)
And, ![K_w=10^{-14}](https://tex.z-dn.net/?f=K_w%3D10%5E%7B-14%7D)
So,
![K_b=\frac {10^{-14}}{1.8\times 10^{-4}}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%20%7B10%5E%7B-14%7D%7D%7B1.8%5Ctimes%2010%5E%7B-4%7D%7D)
![K_b=5.5556\times 10^{-11}](https://tex.z-dn.net/?f=K_b%3D5.5556%5Ctimes%2010%5E%7B-11%7D)
Concentration = 0.35 M
HCOONa ⇒ Na⁺ + HCOO⁻
Consider the ICE take for the formate ion as:
HCOO⁻ + H₂O ⇄ HCOOH + OH⁻
At t=0 0.35 - -
At t =equilibrium (0.35-x) x x
The expression for dissociation constant of sodium formate is:
![K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5BOH%5E-%5D%5BHCOOH%5D%7D%7B%5BHCOO%5E-%5D%7D)
![5.5556\times 10^{-11}=\frac {x^2}{0.35-x}](https://tex.z-dn.net/?f=5.5556%5Ctimes%2010%5E%7B-11%7D%3D%5Cfrac%20%7Bx%5E2%7D%7B0.35-x%7D)
Solving for x, we get:
x = 0.44×10⁻⁵ M
pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64
pH + pOH = 14
So,
<u>pH = 14 - 4.64 = 9.36</u>
Answer: The correct answer is the option: B. An element with eight valence electrons is chemically unstable.
Explanation:
Hello! Let's solve this!
We will analyze each of the options:
A. The group number of the element provides a clue to the number of valence electrons: it is correct, since it provides the number of valence electrons.
B. An element with eight valence electrons is chemically unstable: this is not correct, since elements with eight electrons in the valence shell cannot react because they already have the last complete shell. Therefore, they are chemically stable.
C. The points must be placed one at a time on each side of the chemical symbol: it is correct, because that is the way to make the point diagram.
D. An atom is chemically stable if all the points are paired: this is correct since this verifies that the point diagram has been done well.
We conclude that the correct answer is the option: B. An element with eight valence electrons is chemically unstable.
Hope this helps..... Stay safe and have a Merry Christmas!!!!!!!!! :D
4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂
x=0.824*4/5=0.6592 mol