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3 years ago

If u pass a curve of 3A in a time of 90mins. how much mg will be deposited.

Chemistry

1 answer:

Maslowich3 years ago

8 0

Answer:

$\boxed{\text{2.0 g}}$

Explanation:

1. Write the equation for the half-reaction.

Mg²⁺ + 2e⁻ ⟶ Mg

The number of electrons transferred (z) is 2 mol per mole of Mg.

2. Calculate the number of coulombs

Q = It

$\text{t} = \text{90 min} \times \dfrac{\text{60 s}}{\text{1 min}} = \text{5400 s}\\\\Q = \text{3 C/s} \times \text{ 5400 s} = 16 000 C$

3. Mass of Mg

We can summarize Faraday's laws as

$m = \dfrac{QM}{zF}\\\begin{array}{rcl}m & = &\dfrac{16 000 \times 24.30}{2 \times 96 485}\\& = & \textbf{2.0 g}\\\end{array}\\\text{The mass of Mg deposited is }\boxed{\textbf{2.0 g}}$

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An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

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The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

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Mass of hydrogen, $H$ :

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Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

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3 years ago

If u pass a curve of 3A in a time of 90mins. how much mg will be deposited.​

If u pass a curve of 3A in a time of 90mins. how much mg will be deposited.