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3 years ago

How do scientific tests help determine the properties of substances

Physics

1 answer:

tino4ka555 [31]3 years ago

7 0

It can help determine substances that appear similar but react differently under the same circumstances.

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2. An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in

a_sh-v [17]

Answer:

t = 0.319 s

Explanation:

With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by

v = √T/λ

Linear density is

λ = m / L

λ = 4/20

λ = 0.2 kg / m

The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg

T = W = mg

T = 80 9.8

T = 784 N

The pulse rate is

v = √(784 / 0.2)

v = 62.6 m / s

The time it takes to reach the hook can be searched with kinematics

v = x / t

t = x / v

t = 20 / 62.6

t = 0.319 s

7 0

3 years ago

A transverse wave on a string is described by the wave function

svp [43]

The period of the transverse wave from what we have here is 0.5

<h3>How to find the period of the transverse wave</h3>

The period of a wave can be defined as the time that it would take for the wave to complete one complete vibrational cycle.

The formula with which to get the period is

w = 4π

where w = 4 x 22/7

2π/T = 4π

6.2857/T = 12.57

From here we would have to cross multiply

6.2857 = 12.57T

divide through by 12.57

6.2857/12.57 = T

0.500 = T

Hence we can conclude that the value of T that can determine the period based on the question is 0.500.

Read more on transverse wave here

brainly.com/question/2516098

#SPJ4

5 0

1 year ago

Your family took 6 hours to travel to your destination. The average speed for the first time 2 h 15 min was 160 km/h. For the re

Leni [432]

Answer:

3 h 45 min

Explanation:

6 - 2 = 4

4 - .15 = 3 45

Hopefully this helps you :)

pls mark brainlest ;)

5 0

3 years ago

A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is

Lana71 [14]

Answer:

$m = 0.169 \ kg$

$|v_{max} |= 0.5653 \ m/s$

Explanation:

From the question we are told that

The spring constant is $k = 14 \ N/m$

The maximum extension of the spring is $A = 6.0 \ cm = 0.06 \ m$

The number of oscillation is $n = 30$

The time taken is $t = 20 \ s$

Generally the the angular speed of this oscillations is mathematically represented as

$w = \frac{2 \pi}{T}$

where T is the period which is mathematically represented as

$T = \frac{t}{n}$

substituting values

$T = \frac{20}{30 }$

$T = 0.667 \ s$

Thus

$w = \frac{2 * 3.142 }{ 0.667}$

$w = 9.421 \ rad/s$

this angular speed can also be represented mathematically as

$w = \sqrt{\frac{k}{m} }$

=> $m =\frac{k }{w^2}$

substituting values

$m =\frac{ 15 }{(9.421)^2}$

$m = 0.169 \ kg$

In SHM (simple harmonic motion )the equation for velocity is mathematically represented as

$v = - Awsin (wt)$

The velocity is maximum when $wt = \(90^o) \ or \ 1.5708\ rad$

$v_{max} = - A* w$

=> $|v_{max} |= A* w$

=> $|v_{max} |= 0.06 * 9.421$

=> $|v_{max} |= 0.5653 \ m/s$

5 0

3 years ago

A technician wearing a brass bracelet enclosing area 0.00500 m2 places her hand in a solenoid whose magnetic field is 3.10 T dir

aliya0001 [1]

Explanation:

Given that,

Area enclosed by a brass bracelet, $A=0.005\ m^2$

Initial magnetic field, $B_i=3.1\ T$

The electrical resistance around the circumference of the bracelet is, R = 0.02 ohms

Final magnetic field, $B_f=0.93\ T$

Time, $t=16\ ms=16\times 10^{-3}\ s$

The expression for the induced emf is given by :

$\epsilon=-\dfrac{d\phi}{dt}$

$\phi$ = magnetic flux

$\epsilon=-\dfrac{d(BA)}{dt}$

$\epsilon=-A\dfrac{d(B)}{dt}$

$\epsilon=-A\dfrac{B_f-B_i}{t}$

$\epsilon=-0.005 \times \dfrac{0.93-3.1}{16\times 10^{-3}}$

$\epsilon=0.678\ volts$

So, the induced emf in the bracelet is 0.678 volts.

Using ohm's law to find the induced current as :

V = IR

$I=\dfrac{V}{R}$

$I=\dfrac{0.678}{0.02}$

I = 33.9 A

I = 34 A

So, the induced current in the bracelet is 34 A. Hence, this is the required solution.

5 0

3 years ago