Answer:
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Explanation:dfbgdhzfgbfxgzbfxd
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Answer:
Use the principle of momentum
Initial momentum = final momentum
Momentum formula = Mass * Velocity
Explanation:
Answer:
COMPLETE QUESTION
A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?
Explanation:
Given that,
Extension of spring
x = 0.0208m
Mass attached m = 3.39kg
Additional mass to have a frequency f
Let the additional mass be m
Using Hooke's law
F= kx
Where F = W = mg = 3.39 ×9.81
F = 33.26N
Then,
F = kx
k = F/x
k = 33.26/0.0208
k = 1598.84 N/m
The frequency is given as
f = ½π√k/m
Make m subject of formula
f² = ¼π² •(k/m
4π²f² = k/m
Then, m4π²f² = k
So, m = k/(4π²f²)
So, this is the general formula,
Then let use the frequency above
f = 3Hz
m = 1598.84/(4×π²×3²)
m = 4.5 kg
Explanation:
The force of the roller-coaster track on the cart at the bottom is given by :
, m is mass of roller coaster
Case 1.
R = 60 m v = 16 m/s
Case 2.
R = 15 m v = 8 m/s
Case 3.
R = 30 m v = 4 m/s
Case 4.
R = 45 m v = 4 m/s
Case 5.
R = 30 m v = 16 m/s
Case 6.
R = 15 m v =12 m/s
Ranking from largest to smallest is given by :
F>E>A=B>C>D
