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Kipish [7]
3 years ago
7

A Roller Derby Exhibition recently came to town. They packed the gym for twoconsecutive weekend nights at South's field house. O

n Saturday evening, the68-kg Anna Mosity was moving at 17 m/s when she collided with 76-kg SandraDay O'Klobber who was moving forward at 12 m/s and directly in Anna's path.Anna jumped onto Sandra's back and the two continued moving together atthe same speed. Determine their speed immediately after the collision.
Physics
1 answer:
Alla [95]3 years ago
8 0

Answer:

14.4 m/s

Explanation:

mass of Anna (Ma) = 68 kg

speed of Anna (Va) = 17 m/s

mass of SandraDay (Ms) = 76 kg

speed of SandraDay (Vs) = 12 m/s

We can find their speed (V) immediately after collision from the conservation of momentum where

(Ma x Va) + (Ms + Vs) = (Ma + Ms) x V

where V = speed immediately after collision

(68 x 17) + (76 + 12) = (68 + 76) x V

2068 = 144 V

V = 2068 / 144 = 14.4 m/s

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The minimum height h is 65m so that the car will not fall off the track at the top of the circular part of the loop.

<h3>What is mechanical energy?</h3>

Potential energy plus kinetic energy are combined to form mechanical energy. According to the principle of mechanical energy conservation, mechanical energy is constant in an isolated system when only conservative forces are acting on it. Potential energy increases when an object moves in the opposite direction of a conservative net force. Kinetic energy also changes as an object's speed, not velocity, changes. However, nonconservative forces, such as frictional forces, will always be present in real systems; however, if these forces are of minimal magnitude, mechanical energy changes little, making the idea of its conservation a reasonable approximation.

For completing the vertical circle the minimum speed at the bottom must be \sqrt{5gR}

so conserving mechanical energy

mgh=\frac{1}{2} m (v_{bottom})^{2}

gh=\frac{1}{2} 5gR

⇒ h= \frac{5}{2} \times 26

h = 65m

To learn more about mechanical energy, visit:

brainly.com/question/24443465

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