A Roller Derby Exhibition recently came to town. They packed the gym for twoconsecutive weekend nights at South's field house. O
1 answer:
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The velocity of the ball and the man is 0.259 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, in an isolated system, the total momentum before and after the collision must be conserved. Therefore, for the ball-man system, we can write:
where:
is the mass of the ball
is the initial velocity of the ball
is the mass of the man
is the initial velocity of the man
is the final velocity of the man and the ball after the collision
Re-arranging the equation and substituting the values, we find the final velocity:
So, the man and the ball slides on the ice at 0.259 m/s.
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Answer:
La escala del termómetro ''A'' es grados Celsius.
La escala del termómetro ''B'' es grados Fahrenheit.
Explanation:
Para hallar en qué escalas están los termómetros partimos de que la mezcla a la cuál se midió su temperatura mantuvo su temperatura constante.
Esto quiere decir que los termómetros están expresando la misma temperatura pero en una escala distinta.
Sabemos que dada una temperatura en grados Celsius ''C'' si la queremos convertir a grados Fahrenheit ''F'' debemos utilizar la siguiente ecuación :
(I)
Ahora, si reemplazamos y asumimos que la temperatura de 18° es en grados Celsius, entonces si reemplazamos en la ecuación (I) deberíamos obtener
⇒
Efectivamente obtenemos el valor esperado. Finalmente, corroboramos que la temperatura del termómetro ''A'' está medida en grados Celsius y la temperatura del termómetro ''B'' en grados Fahrenheit.
The coefficient of friction must be 0.196
Explanation:
For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:
where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:
is the coefficient of friction between the tires and the road
m is the mass of the car
is the acceleration of gravity
v is the speed of the car
r is the radius of the curve
In this problem,
r = 750 m is the radius
is the speed
And solving for , we find the coefficient of friction required to keep the car in circular motion:
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Answer:
Bulk modulus = 1.35 × Pa
Explanation:
given data
density = 1400 kg/m³
frequency = 370 Hz
wavelength = 8.40 m
solution
we get here bulk modulus of the liquid that is
we know Bulk Modulus = ...............
here is density i.e 1400 kg/m³
and v is = frequency × wavelength
v = 370 × 8.40 = 3108 m/s
so here bulk modulus will be as
Bulk modulus = 3108² × 1400
Bulk modulus = 1.35 × Pa