Answer: Imidogen
Explanation: I just looked it up.
Answer:
26.73 mg.
Explanation:
- Firstly, we can calculate the no. of moles of magnesium chlorate (Mg(ClO₃)₂):
no. of moles of magnesium chlorate (Mg(ClO₃)₂) = mass/molar mass = (72.03 mg)/(191.21 g/mol) = 0.377 mmol.
<em>Every 1.0 mole of magnesium chlorate (Mg(ClO₃)₂) contains 2.0 moles of Cl.</em>
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∴ The no. of moles of Cl in magnesium chlorate (Mg(ClO₃)₂) = 2(0.377 mmol) = 0.754 mmol.
∴ The mass of Cl are found in 72.03 mg of magnesium chlorate (Mg(ClO₃)₂) = (no. of moles of Cl)(atomic mass of Cl) = (0.754 mmol)(35.453 g/mol) = 26.73 mg.
Answer:
The concentration of the dilute sample will be 0.361 g/ml
Explanation:
If a solution is diluted into 1:10 ratio then the amount of solute of that solution will be decreased by 10 times.
The initial concentration of the stock solution was 3.61g/ml but when the solution is diluted in 1:10 ratio the solute concentration is also decreased by 10 times.SO at present the solute concentration becomes 3.61/10=0.361 g/ml.