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bogdanovich [222]
3 years ago
9

Question 9 rank the effective nuclear charge z * experienced by a valence electron in each of these atoms:

Chemistry
1 answer:
AlexFokin [52]3 years ago
7 0
To rank the effective nuclear charge Z* experienced by a valence electrons of a set of atoms that belong to a same period, you only need to apply the rule of trend: it increases as you move from left to right in the period.

So, lets do it for these atoms: P,  Al, Si, Cl

The belong to a same period and the order is Al, Si, P, Cl (just see a periodic table). So the rank is Al < Si < P < Cl

Now, lets do it for these atoms:, Be, Ne, O, C

They belong to the second period. The order is Be, C, O, Ne

So, the rank is Be < C < O < Ne.


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2 years ago
How many grams are in 5 mols of KOH​
elena55 [62]

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Explanation:

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3 years ago
Sn=0.14 (E) <br>Sn+2 = -0.15(E) <br>Which form of tin is the stronger reducing agent? OS O Sn +2? ​
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0.14

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2 years ago
Chemistry! Help! Please!! Thanks
Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

<em>Structure 1 </em>

  1. Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
  2. Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
  3. Number the main chain from the end closest to a substituent.
  4. Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
  5. Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

<em>Structure 2</em>

  1. 5C. Base name = pentane
  2. Four methyl groups.
  3. Number from the left-hand end.
  4. If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
  5. The name is 2,2,3,3-tetramethylpentane.

<em>Structure 3 </em>

  1. Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the <em>-ne</em> ending of the alkane to get the root name <em>hexa-</em>.
  2. (No substituents).
  3. Number the main chain from the end closest to a double bond.
  4. If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
  5. Put the functional group name at the end of the root name (hexa-2,4-diene).

<em>Note</em>: The name 2,4-hexadiene is <em>acceptable</em>, but the <em>Preferred IUPAC Name</em> puts the locating numbers as close as possible in front of the groups they locate.

7 0
4 years ago
A student sets up the following equation to convert a measurement.
Sholpan [36]

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

6 0
3 years ago
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