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ipn [44]
3 years ago
14

if lithium loses an electron to become li+ what is the average atomic mass of the lithium ion? explain how you arrived at your a

nswer
Chemistry
2 answers:
Pavlova-9 [17]3 years ago
8 0
The mass of an electron 1/1823 amu's = 0.0005 amu's... the average mass of litium is 6.941 amu's. by losing an electron, the mass of average atomic mass of the Lithium doesn't really change much. 
Aliun [14]3 years ago
4 0

<u>Answer:</u> The average atomic mass of the lithium ion remains the same as lithium atom which is 6.94 amu

<u>Explanation:</u>

Mass number is defined as the sum of number of protons and number of neutrons present in an atom. It is represented as A.

A = Mass number = Number of neutrons + Number of protons.

An ion is formed when a neutral atom looses or gains electrons.

  • When an atom looses electrons, it results in the formation of positive ion known as cation.
  • When an atom gains electrons, it results in the formation of negative ion known as anion.

So, the loss or gain of electrons does not effect the mass number of an atom. Thus, when lithium atom looses an electron to form lithium ion (Li^+), the average atomic mass of the ion remains the same as the neutral atom.

Average atomic mass of lithium atom = 6.94 amu

Hence, the average atomic mass of lithium ion is 6.94 amu.

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Hoochie [10]

The compound : C₄₀H₄₄N₄O

<h3>Further explanation</h3>

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The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.  

• Determine the mole ratio by dividing the percentage by the atomic mass

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\tt \dfrac{80.66}{12}\div \dfrac{7.39}{1}\div \dfrac{9.39}{14}\div \dfrac{2.68}{16}\\\\6.722\div 7.39\div 0.671\div 0.1675\rightarrow divide~by~smallest(0.1675)\\\\40\div 44\div 4\div 1

3 0
3 years ago
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
How many moles are in 9.50 x 1022 molecules of CO? Be sure to ALL work below and report your answer using the correct number of
eimsori [14]

Answer:

0.158 moles

Explanation:

We are given;

9.50 x 10^22 molecules of CO

We are required to determine the number of moles;

We need to know;

1 mole of a compound = 6.022 × 10^23 molecules

Therefore;

9.50 x 10^22 molecules of CO will be equivalent to;

= 9.50 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole

= 0.158 moles

Therefore, the number of moles are 0.158 moles

4 0
3 years ago
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Liquidity metric is the other name
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