Question

PLEASE HELP ME In the following reaction, what element is made?

Answer 1

Answer: $^{244}_{97}\textrm {Bk}$

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is:

$^{241}_{95}\textrm{Am}+^{4}_{2}\textrm{He}\rightarrow ^{A}_{Z}\textrm {}+^{1}_{0}n$

To calculate A:

Total mass on reactant side = total mass on product side

$241+4=A+1$

$A=244$

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

95 + 2 = Z + 0

Z = 97

Thus the element will be berkelium with atomic number of 97 and element will be represented as $^{244}_{97}\textrm {Bk}$

Answer 2

organic compounds is ur awnser