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4 years ago

When cartographers represent the three-dimensional earth in two dimensions, what is likely to occur?

Physics

2 answers:

Harlamova29_29 [7]4 years ago

7 0

Distortion is likely to occur

Sladkaya [172]4 years ago

6 0

distortion is most likely to occur.

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A stone is dropped from the upper observation deck of a tower, 750 m above the ground. (assume g = 9.8 m/s2.) (a) find the dista

Gekata [30.6K]

(a) The stone moves by uniform accelerated motion, with constant acceleration $g=9.81 m/s^2$ directed downwards, and its initial vertical position at time t=0 is 750 m. So, the vertical position (in meters) at any time t can be written as
$y(t)= y_0 - \frac{1}{2}gt^2= 750 - 4.9 t^2$

(b) The time the stone takes to reach the ground is the time at which the vertical position of the stone becomes zero: y(t)=0. So, we can write
$750-4.9 t^2 = 0$
from which we find the time t after which the stone reaches the ground:
$t= \sqrt{\frac{750 m}{4.9 m/s^2 }}= 12.37 s$

(c) The velocity of the stone at time t can be written as
$v(t) = -gt$
because it is an accelerated motion with initial speed zero. Substituting t=12.37 s, we find the final velocity of the stone:
$v(12.37 s)=-(9.81 m/s^2)(12.37 s)=-121.3 m/s$

(d) if the stone has an initial velocity of $v_0 = 6 m/s$ , then its law of motion would be
$y(t)=y_0 - v_0t - \frac{1}{2}gt^2$
and we can find the time it needs to reach the ground by requiring again y(t)=0:
$0=750 - 6t - 4.9 t^2$
which has two solutions: one is negative so we neglect it, while the second one is t=11.78 s, so this is the time after which the stone reaches the ground.

5 0

3 years ago

Vector A points north and vector B points east. If c = B - A , then vector C points where?

Sergio [31]

Answer:

South of East

Explanation:

7 0

3 years ago

a foul ball is hit into the stands at a baseball game. the ball rises to a height of 38 meters and is caught on its way down by

lisov135 [29]

The velocity of the ball when it was caught is 12.52 m/s.

<em>"Your question is not complete it seems to be missing the following, information"</em>,

find the velocity of the ball when it was caught.

The given parameters;

maximum height above the ground reached by the ball, H = 38 m

height above the ground where the ball was caught, h = 30 m

The height traveled by the ball when it was caught is calculated as follows;

y = H - h

y = 38 - 30 = 8 m

The velocity of the ball when it was caught is calculated as;

$v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s$

Thus, the velocity of the ball when it was caught is 12.52 m/s.

Learn more here: brainly.com/question/14582703

4 0

3 years ago

While traveling along a highway a drivers velocity is 9m/s. In 12 seconds how far has the car gone?

kupik [55]

While travelling along a highway a drivers velocity is 9 m/s. In 12 seconds, the car has gone for 108 m.

<u>Explanation:</u>

The car travelling along the highway has a uniform velocity of 9 m/s. therefore to calculate the distance travelled by the car with the uniform velocity in 12 seconds, simple formula of velocity is to be employed.

Thereby, as we know that

$\text {velocity}=\frac{\text {displacement}}{\text {time}}$

The displacement is along the highway with uniform motion, therefore, distance=displacement

Given that,

Velocity = 9 m/s

Time = 12 s

Putting the values in the formula, we get,

$9 = \frac{d}{12}$

$d=12 \times 9=108 \mathrm{m}$

Therefore, the car travels for 108 m in the 12 seconds while travelling along highway with 9 m/s of velocity.

5 0

3 years ago

Exercise can help to prevent which potential health problem? a). head lice b). chicken pox c). heart disease d). strep throat

Mrac [35]

Answer:

Explanation:

Exercise also increases your levels of HDL cholesterol, the "good" cholesterol that lowers heart disease risk by flushing the artery-clogging LDL or "bad" cholesterol out of your system.

5 0

3 years ago

Read 2 more answers