Well, my German isn't as sharp as it used to be, but it looks like you're supposed to use the symbols at the top and draw two circuits ... one where the switch is closed and the light is shining, the other where the switch is open and the light is out.
That should be pretty easy for you. Just hook up one battery, one switch, and one light, all in series. Then opening and closing the switch makes the light go on and off.
Answer:
1a.5km
2a. 31536000 seconds
2b.2800000 centimeters
2c.45,000,000 Milligrams
2d.0.0141667 m/s
2e.2.592 x 10^10 km/day
2f .8.23x10^-7m
2g.0.0000085 m3
Explanation:
1a.(25km/5)(1000m/1km)(1h/3600s) =(5km)( 1) (1) =5km
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Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :
v is the speed of the stone just before it hits the ground
v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
The perimeter of ΔWXY is : ( D ) 14.5 cm
<u>Calculating the </u><u>perimeter </u><u>of ΔWXY</u>
QR = WY / 2
RS = XW / 2
QS = XY / 2
Given that : QR = 2.93 cm , RS = 2.04 cm, QS = 2.28 cm
Therefore
Perimeter of ΔWXY = ∑ WY + XW + XY
= 2SR + 2QS + 2QR
= 2(2.04) + 2(2.28) + 2(2.93)
= 14.5 cm
Hence we can conclude that the perimeter of ΔWXY = 14.5 cm
learn more about perimeter calculations : brainly.com/question/24744445
Answer:
42Amp
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