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blondinia [14]
4 years ago
15

The force to move something toword you is called​

Physics
1 answer:
faust18 [17]4 years ago
6 0

Answer:

Work

Explanation:

work is defined as the use of force to move an object. For work to be done, the force must be applied in the same direction that the object moves.

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Consider a metal bar of initial length L and cross-sectional area A. The Young's modulus of the material of the bar is Y. Find t
RUDIKE [14]

Answer:

Spring constant = YA / L

Explanation:

Let F be the force being applied on cross sectional area A of metal bar due to which an extension of ΔL is obtained in the wire of length L then

stress = F / A

strain = ΔL /L

Young's modulus = ( F / A ) / (ΔL /L)

Y = ( F L / A ΔL )

( F / ΔL ) = ( YA / L )

Spring constant = ( F / ΔL )

Spring constant = YA / L

6 0
3 years ago
_______is the product of a force and the time during which the force acts
saul85 [17]

Answer:

impulse is the product of a force and the time during which the force acts

Explanation:

i hope this will help you :)

7 0
3 years ago
How does Bohr’s model of the atom compare with Thomson’s model?
larisa [96]

Answer:

They both describe atoms as being made up of positive and negative matter.

Explanation:

In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:

- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere

- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.

4 0
4 years ago
Read 2 more answers
wo parallel plates of area 100cm2are given charges of equal magnitudes 8.9 ×10−7C but opposite signs. The electric field within
abruzzese [7]

(a) 7.18

The electric field within a parallel plate capacitor with dielectric is given by:

E=\frac{\sigma}{k \epsilon_0} (1)

where

\sigma is the surface charge density

k is the dielectric constant

\epsilon_0 is the vacuum permittivity

The area of the plates in this capacitor is

A=100 cm^2 = 100\cdot 10^{-4} m^2

while the charge is

Q=8.9\cdot 10^{-7}C

So the surface charge density is

\sigma = \frac{Q}{A}=\frac{8.9\cdot 10^{-7} C}{100\cdot 10^{-4} m^2}=8.9\cdot 10^{-5} C/m^2

The electric field is

E=1.4\cdot 10^6 V/m

So we can re-arrange eq.(1) to find k:

k=\frac{\sigma}{E \epsilon_0}=\frac{8.9\cdot 10^{-5} C/m^2}{(1.4\cdot 10^6 V/m)(8.85\cdot 10^{-12} F/m)}=7.18

(b) 7.66\cdot 10^{-7}C

The surface charge density induced on each dielectric surface is given by

\sigma' = \sigma (1-\frac{1}{k})

where

\sigma=8.9\cdot 10^{-5} C/m^2 is the initial charge density

k = 7.18 is the dielectric constant

Substituting,

\sigma' = (8.9\cdot 10^{-5} C/m^2) (1-\frac{1}{7.18})=7.66\cdot 10^{5} C/m^2

And by multiplying by the area, we find the charge induced on each surface:

Q' = \sigma' A = (7.66\cdot 10^{-5} C/m^2)(100 \cdot 10^{-4}m^2)=7.66\cdot 10^{-7}C

6 0
3 years ago
Jamie is sliding down a slide what kind of motion
Alchen [17]

Answer:

Explanation:

Down man

4 0
3 years ago
Read 2 more answers
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