Answer:
The concentration of the newly prepared solution is 8 * 10^-5 M
Explanation:
The most common way to solve this problem is to use the following formula
c1*V1 = c2*V2
with c1 = 1 * 10^-3 M
with V1 = 20 mL = 0.02 L
with c2 = TO BE DETERMINED
with V2 = 250 mL = O.250 L
10^-3 * 0.02 L = c2 * 0.250L
0.00002 = c2 * 0.250L
c2 = 0.00002 / 0.250 L
c2 = 0.00008 M = 8 * 10^-5 M
The concentration of the newly prepared solution is 8 * 10^-5 M
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.
