Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
Explanation:
Given: 
= 0.2 kg, 
= 0.15 kg
= 2 m/s, 
= 0 m/s, 
= ?, 
= 1.5 m/s
Formula used is as follows.
where,
v = velocity before collision
v' = velocity after collision
Substitute the values into above formula as follows.
Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
The correct answer is 9.7 grams because mg are 1,000 difference to grams.
Hello!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply
Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
Have a nice day!
