A quantum system has three energy levels, so three wavelengths appear in its emission spectrum. the shortest observed wavelength
1 answer:
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The acceleration of the electron is larger than the acceleration of the proton.
The reason for this is that the mass of the electron is smaller (about 1000 times smaller) than the mass of the proton. The two particles have same charge (e), so they experience the same force under the same electric field E:
However, according to Newton's second law, the force is the product between the mass particle, m, and its acceleration, a:
which can be rewritten as
we said that the force exerted on the two particles, F, is the same, while the mass of the electron is smaller: therefore, from the last formula we see that the acceleration of the electron will be larger than that of the proton.
The reason for this is that the mass of the electron is smaller (about 1000 times smaller) than the mass of the proton. The two particles have same charge (e), so they experience the same force under the same electric field E:
However, according to Newton's second law, the force is the product between the mass particle, m, and its acceleration, a:
which can be rewritten as
we said that the force exerted on the two particles, F, is the same, while the mass of the electron is smaller: therefore, from the last formula we see that the acceleration of the electron will be larger than that of the proton.
Answer:
(A) considering the charge "q" evenly distributed, applying the technique of charge integration for finite charges, you obtain the expression for the potential along any point in the Z-axis:
With been the vacuum permittivity
(B) The expression for the magnitude of the E(z) electric field along the Z-axis is:
Explanation:
(A) Considering a uniform linear density on the ring, then:
(1)⇒
(2)⇒
(3)
Applying the technique of charge integration for finite charges:
(4)
Been r' the distance between the charge and the observation point and a, b limits of integration of the charge. In this case a=2π and b=0.
Using cylindrical coordinates, the distance between a point of the Z-axis and a point of a ring with R radius is:
(5)
Using the expressions (1),(4) and (5) you obtain:
Integrating results:
(S_a)
(B) For the expression of the magnitude of the field E(z), is important to remember:
(6)
But in this case you only work in the z variable, soo the expression (6) can be rewritten as:
(7)
Using expression (7) and (S_a), you get the expression of the magnitude of the field E(z):
(S_b)