Answer:
NaI
Explanation:
Sodium has a charge of 1+ and iodine has a charge of 1-. They exist in a one-to-one ratio. Because they are ionic compounds, they go for the lowest ratio available.
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?
<h3><u>Answer;</u></h3>
= 78 g of NaOH
<h3><u>Explanation;</u></h3>
Concentration = Moles of solute/Volume of solution
Thus;
Moles of the solute = Volume × Concentration
= 7.80 Moles/L × 0.250 L
= 1.95 moles
But; 1 mole of NaOH = 40.0 g
Thus;
Mass of NaOH = moles × molar mass
= 1.95 moles × 40 g/mole
<u> = 78 g of NaOH</u>
Answer:
30.4 torr
Explanation:
We have all the information which is required to solve this question ( more than we even need as the molecular weight)
Ptotal = Ptoluene + Pbenzene
Ptotal = Xtoluene Pºtoluene + XbenzenePºbenzene
The mole fraction is given by the formula:
X =number of moles / total number of moles
Xtoluene = 8.53 / (2.15+8.53) = 0.80
Xbenzene = 2.15 / 10.68 = 0.20
⇒Ptotal = 0.80 x 14torr + 0.20 x 96 torr = 30.4 torr
