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3 years ago

How are frequency and wave period related?

1 answer:

6 0

-- The unit of frequency is "per second" (Hz), which is [reciprocal time].

-- The unit of period is "second", which is [time].

Do you see where this is going ?

'Frequency' and 'period' are reciprocals of each other.

For any wave ...

Period = (1) / (frequency) .

Frequency = (1) / (period) .

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Billy drops a ball from a height of 1 m. The ball bounces back to a height of 0.8 m, then

Andreas93 [3]

Answer:

The displacement is $\Delta H = - 1 \ m$

The distance is $D = 4 \ m$

Explanation:

From the question we are told that

The height from which the ball is dropped is $h = 1 \ m$

The height attained at the first bounce is $h_1 = 0.8 \ m$

The height attained at the second bounce is $h_2 = 0.5 \ m$

The height attained at the third bounce is $h_3 = 0.2 \ m$

Note : When calculating displacement we consider the direction of motion

Generally given that upward is positive the total displacement of the ball is mathematically represented as

$\Delta H = (0 - h ) + ( h_1 - h_1 ) + (h_2 - h_2 )+ (h_3 - h_3)$

Here the 0 show that there was no bounce back to the point where Billy released the ball

$\Delta H = (0 - 1 ) + ( 0.8- 0.8 ) + (0.5 - 0.5 )+ (0.2 - 0.2)$

=> $\Delta H = - 1 \ m$

Generally the distance covered by the ball is mathematically represented as

$D = h + 2h_2 + 2h_3 + 2h_3$

The 2 shows that the ball traveled the height two times

$D = 1 + 2* 0.8 + 2* 0.5 + 2* 0.2$

=> $D = 4 \ m$

5 0

3 years ago

How long is a football field?

Nana76 [90]

Answer:

91.44 meters or 300 feet

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3 years ago

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Leght of a chief of a circle

WINSTONCH [101]

Answer: Your question does not make sense

Explanation:

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4 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3,650 rev/min. when switched off, it rotates through 48.0 re

AlladinOne [14]

First of all we need to convert everything into SI units.

Let's start with the initial angular speed, $\omega _i = 3650 rev/min$ . Keeping in mind that
$1 rev = 2 \pi rad$
$1 min=60 s$
we have
$\omega _i = 3650 \frac{rev}{min} \cdot \frac{2 \pi rad/rev}{60 s/min} =382.0 rad/s$

And we should also convert the angle covered by the centrifuge:
$\theta = 48.0 rev= 48.0 rev \cdot 2 \pi \frac{rad}{rev}=301.4 rad$

This is the angle covered by the centrifuge before it stops, so its final angular speed is $\omega_f =0$ .

To solve the problem we can use the equivalent of
$2aS = v_f^2 -v_i^2$
of an uniformly accelerated motion but for a rotational motion. It will be
$2 \alpha \theta = \omega_f^2-\omega_i^2$
And by substituting the numbers, we can find the value of $\alpha$ , the angular acceleration:
$\alpha=- \frac{\omega_i^2}{2 \theta}=- \frac{(382 rad/s)^2}{2 \cdot 301.4 rad}=-242.1 rad/s^2$

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3 years ago

The cat righting reflex is a cat's innate ability to orient itself as it falls in order to land on its feet. The righting reflex

Inessa [10]

Answer:

The solution is shown in the picture attached below

Explanation:

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3 years ago