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3 years ago

a is any object that is launched into the air with an initial velocity and moves in the air only ander the influence of gravity

Physics

1 answer:

dexar [7]3 years ago

8 0

Answer:

Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Explanation:

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What would be the length of a day(that is, the time required forone

Alex17521 [72]

Answer:

T = 5,06 10³ s

Explanation:

For this exercise, let's use Newton's second law, where force is the force of gravitational attraction

F = m a

The acceleration is centripetal

a = v² / r

Let's replace

G m $M_{e}$ / $R_{e}$ ² = m v² / $R_{e}$

G $M_{e}$ / $R_{e}$ = v²

The velocity module is constant, so we can use the equation of uniform motion

v = d / t

Where the distance is the length of the circle and in this case the time is called the period

d = 2π $R_{e}$

We replace

(2π $R_{e}$ / T)² = G $M_{e}$ / $R_{e}$

T² = 4π² $R_{e}$ ³ / G $M_{e}$

T = √ 4π² $R_{e}$ ³ / G $M_{e}$

Let's calculate

T = √ (4π² (6.37 10⁶)³ / 6.67 10⁻¹¹ 5.98 10²⁴)

T = √ (255.83 10⁵) = √ (25.583 10⁶)

T = 5,05796 10³ s

4 0

3 years ago

What type of diagram chart in a service manual can be used to easily service an electronic circuit board with ICs?

Y_Kistochka [10]

<span>That could be letter B: flowchart. Flowchart diagrams can be used to easily service an electronic circuit board with ICs because they let you see the flow of the current as you could imagine it. You can use different shapes to further your explanation and illustration on how the electricity flows from a source, to its medium to the switches. You could also decide on flowcharts and be able to see where that decision leads you and you could also try to learn different decision methods which is basically illustrated on the chart.</span>

3 0

3 years ago

Four charges are located at the corners of a square. Each side of the square is 37 m. The left two charges have a positive charg

nadezda [96]

Answer:

E = 781.12 N/C

Explanation:

Look at the attached graphic:

The 20µC charges are positive , then, the electric fields leave the charge.

The 22µC charges are negative, then, the electric fields enter the charge.

The electric field due to each of the charges is calculated by Coulomb's law:

E= k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

Problem development

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

E₁, E₂, E₃, E₄: Electric field at point P due to charge q₁, q₂, q₃, and q₄ respectively

The electric field in the direction of the y axis at the point P in the center of the square is equal to zero because the sum of the vertical components upwards is equal to the sum of the vertical components downwards.

Calculation of the electric field in the direction of the x-axis in the center of the square (point P)

Eₓ = E₁ₓ + E₂ₓ + E₃ₓ + E₄ₓ

$d = \sqrt{18.5^2+ 18.5^2} =26.16m$