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3 years ago

a is any object that is launched into the air with an initial velocity and moves in the air only ander the influence of gravity

Physics

1 answer:

dexar [7]3 years ago

8 0

Answer:

Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Explanation:

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Stade avogadro's hypothesis what are its applications, prove that hydrogen hydrogen and oxygen gases

natita [175]

Answer:

Applications of Avogadro's hypothesis:

In explaining Gay Lussac's law of gaseous volumes.

In determining the atomicity of gasses.

In determining the molecular formula of a gas.

In establishing the relationship between relative molecular mass and vapor density.

Explanation:

3 0

3 years ago

How long will it take for a car to travel 200 km if it has an average speed of 55 km/hr?

andreyandreev [35.5K]

Answer: Approximately 3.65 hours

Explanation:

55 km/h x 3.65 hrs = 200.75 Km/h

4 0

3 years ago

Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential

mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0

3 years ago

Plz guys I again need help

lara [203]

Answer:

idk

Explanation:

7 0

4 years ago

Read 2 more answers

How high must you lift a 25 Newton book for it to have the same increase in potential energy as a 20 Newton book that was lifted

Annette [7]

Given :

An object with weight 20 N was lifted to 0.5 meters.

To Find :

How high must you lift a 25 Newton book for it to have the same increase in potential energy as the given book.

Solution :

Since both have same potential energy :

$P.E_2 = P.E_1\\\\W_2h_2 = W_1h_1$

Putting all given values in above equation :

$25h_2 = 20\times 0.5\\\\h_2 = \dfrac{20\times 0.5}{25}\\\\h_2 = 0.4\ m$

Therefore, book with same potential energy is at a height of 0.4 m.

4 0

3 years ago