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3 years ago

a is any object that is launched into the air with an initial velocity and moves in the air only ander the influence of gravity

Physics

1 answer:

dexar [7]3 years ago

8 0

Answer:

Projectile motion is the motion of an object thrown (projected) into the air. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Explanation:

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The unique name given to each organism ; made up of Genus and species..is..?

True [87]

A binomial nomenclature, more commonly referred to as a scientific name.

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4 years ago

A starter pistol is fired 150m away from the spectators who hear the gun 0.5s after they see it fired. How fast does sound trave

Natali [406]

Answer:

300m/s

Explanation:

speed = distance/time

150/0.5

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3 years ago

If a body of mass 10 kg is pushed with a force of 15N, then the acceleration of the body is

sladkih [1.3K]

Answer:

1.5m/s2

Explanation:

F=ma

a=F/m

a=15/10

a=1.5m/s2

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3 years ago

The diagram below shows the force exerted on object m1 due to the gravitational attraction between m1 and m2. What is true about

gladu [14]

Answer: B. It is directed to the left.

Explanation:

Gravitational force is an attractive force, this is stated by Newton's law of Gravitation:

<em>"The force exerted between two bodies of masses m1 and m2 and separated by a distance is equal to the product of their masses and inversely proportional to the square of the distance"</em>

This means both m1 and m2 are mutually attracted.

Hence, if the force exerted on m1 by m2 is directed to the right, the force exerted on m2 by m1 must be logically <u>directed to the left.</u>

8 0

3 years ago

An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 14.2 rad/s. Calcula

zubka84 [21]

Answer:

0.04865 m

Explanation:

k = Spring Constant

m = Mass

d = Distance

g = Acceleration due to gravity = 9.81 m/s²

Angular frequency is given by

$\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow \dfrac{k}{m}=\omega^2\\\Rightarrow \dfrac{k}{m}=14.2^2$

At equilibrium we have

$kd=mg\\\Rightarrow d=\dfrac{mg}{k}\\\Rightarrow d=\dfrac{g}{\omega^2}\\\Rightarrow d=\dfrac{9.81}{14.2^2}\\\Rightarrow d=0.04865\ m$

The distance by which the spring stretches from its unstrained length is 0.04865 m

7 0

3 years ago