How much force is needed to accelerate a 15kg bowling ball at 2 m/s^2

Can a constant magnetic field set into motion an electron initially at rest? Explain your answer.

Vinvika [58]

No, a constant magnetic field cannot set an electron initially at rest into motion

A force that accelerates a particle is necessary to change its velocity. The magnetic force is inversely proportional to the particle's speed. There cannot be a magnetic force acting on a moving particle, according to Einstein. A flux is a precise description of the greater-than-unity magnetic determine involving energy currents and magnet resources. The magnetic flux in a stage is actually selected apart from each some sort of route and also a degree (or durability); therefore, it is just a vector industry. The magnetic flux is usually defined as the Lorentz force that acts on moving galvanic costs.

To know more about Lorentz force refer to brainly.com/question/15552911

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5 0

2 years ago

For the following types

Ad libitum [116K]

Answer: In order of increasing frequency and decreasing wavelength these are: radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

4 0

3 years ago

Ranking Task: The Electromagnetic Spectrum

shutvik [7]

The increasing order of the wavelength from left to right are as follows Gamma Rays < X-rays < UV rays < visible rays < infrared rays < microwaves < radio waves.

The electromagnetic spectrum consists of many waves which are made up of electric field and the magnetic field.

It is said that the electromagnetic wave behaves like particle as well as the wave.

The particle like pieces of the wave are called photons which contains the energy of the wave and the electromagnetic waves are primarily decided by the wavelength and the frequency of the wave.

The group of electromagnetic waves are known as electromagnetic spectrum.

The electromagnetic wave in the order of increasing wavelength are Gamma Rays < X-rays < UV rays < visible rays < infrared rays < microwaves < radio waves.

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8 0

1 year ago

Technician A says that gears may be used to apply torque to other rotating parts. Technician B says that gears may be used to mu

Goryan [66]

Answer:

Both technicians are right.

Explanation:

Torque is defined as a rotational force that can be calculated by the formula T= F.d. Being F the force applied to a body to make it rotate and d the distance since the force is applied.

$T= F . d$

So technician A is saying that gear can apply a torque to another gear, and that is true because it’s applying a rotational force to the gear next to it, in simple terms -anytime I make something rotate, I'm generating a torque-. And for technician B, the torque also can vary as a function of the distance of the force applied (size of the gear), so, it can multiply the torque and change the rotation speed.

5 0

4 years ago

A toy of mass 0.190-kg is undergoing SHM on the end of a horizontal spring with force constant k = 350 N/m . When the toy is a d

vagabundo [1.1K]

Answer

a)0.0495 J

b)0.01681 m

c)0.7218 m/s

Explanation:

Given

Mass of the.toy M = 0.190 kg

force constant k = 350 N/m

Displacement from equilibrium x = 0.0140 m

Speed v = 0.400 m/s

a)What is the toy's total energy at any point of its motion?

The total energy at any point of it's motion can be calculated by adding together both the potential and kinetic energy of the toy, since it's posses potential energy when at rest and kinetic energy at motion

Total energy E = kinetic energy + potential energy

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.190)(0.4)² + ¹/₂ (350)(0.0140)²

E = 0.0495 J

Hence,the total energy is 0.0495 J

b) the amplitude of the motion can be calculated using below formula

Let amplitude = A

E = ¹/₂KA²

if we make Amplitude A the subject of the formula we have

A=√(2E/k)

But we have calculated our E up there, our K was given in question then if we substitute we have

A= √(2×0.0495)/350

Ans: 0.01681 m

Hence, our Amplitude is 0.01681 m

c) the the toy's maximum speed during its motion can be calculated using the expression below

Let maximum speed = vmax

E = (1/2)M * vmax^2

If we make vmax the subject of the formula we have

vmax =√(2E/m)

vmax= √(2×0.0495)/0.190

vmax=0.7218 m/s

Hence our vmax is 0.7218 m/s

8 0

3 years ago